struts多模块配置问题

Question

将struts-config-user.xml中的path="/user/userLogin"改为path="/userLogin"

Answer 1

另外在web.xml中
<init-param>
      <param-name>config/user</param-name>
      <param-value>/WEB-INF/config/struts-config-user.xml</param-value>
</init-param>
应该改成
<init-param>
      <param-name>config/user</param-name>
      <param-value>/WEB-INF/user/struts-config-user.xml</param-value>
</init-param>
struts-config.xml和struts-config-user.xml最好不要在相同的路径下
<param-name>config/user</param-name>和<param-value>/WEB-INF/user/struts-config-user.xml</param-value>中的user应该保持相同

Answer 2

你在WEB-INF下应该新建一个user文件夹，然后将struts-config-user.xml放在里面

Answer 3

高手,按你说的我已经在web-inf下建了一个目录user,把struts-config-user.xml放进去了
然后在root下建了一个user,把login.jsp放进去了
然后现在的web.xml配置如下:
<init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/config/struts-config.xml</param-value>
    </init-param>
     <init-param>
      <param-name>config/user</param-name>
      <param-value>/WEB-INF/user/struts-config-user.xml</param-value>
    </init-param>
struts-config-user.xml配置如下:
    <action input="/user/login.jsp" 
       name="memberForm"
               parameter="call"
       path="/userLogin" 
       scope="session" 
       type="com.dodo.struts.action.UserLoginAction" 
       validate="true">  
       <forward name="suc" path="/member.jsp" />
       <forward name="loginFail" path="/login.jsp" />
    </action>
页面如下:
<html:form action="/userLogin.do?call=login" method="post" onsubmit="return validateMemberForm(this);">
<table width="452" height="263"  border="0" align="center" cellpadding="0" cellspacing="5" background="../images/login-Bg.jpg">
              <tr valign="bottom">
                <td width="39%" height="87"><div align="right"><bean:message key="member.email" bundle=""/></div></td>
                <td width="61%">
                  <div align="left"><html:text property="email" styleClass="form-border" size="17" maxlength="25"/> </div></td>
              </tr>
              <tr>
                <td height="106"><div align="right"><bean:message key="member.password" bundle="" /></div></td>
                <td>
                  <div align="left"><html:password property="password" styleClass="form-border" size="17" maxlength="25"/> </div></td>
              </tr>
              <tr>
                <td height="24" colspan="2"><table width="80%"  border="0" align="center" cellpadding="0" cellspacing="0">
                  <tr>
                    <td><html:submit styleClass="form-border"/></td>
                    <td><html:cancel styleClass="form-border"/></td>
                  </tr>
                </table></td>
                </tr>
              <tr>
                <td height="18">&nbsp;</td>
                <td>&nbsp;</td>
              </tr>
            </table>
</html:form>
<html:javascript formName="memberForm"/>
错误信息还是找不到action:
javax.servlet.ServletException: Cannot retrieve mapping for action /userLogin
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:848)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:781)
org.apache.jsp.user.login_jsp._jspService(org.apache.jsp.user.login_jsp:110)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:322)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.extremecomponents.table.filter.AbstractExportFilter.doFilter(AbstractExportFilter.java:49)
com.dodo.util.SetCharacterEncodingFilter.doFilter(SetCharacterEncodingFilter.java:63)
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter.doFilter(UrlRewriteFilter.java:738)
跪求高手

Answer 4

web.xml部分配置如下:
<servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/config/struts-config.xml,
                   /WEB-INF/config/struts-config-user.xml,
                   /WEB-INF/config/struts-config-product.xml
      </param-value>
    </init-param>     <load-on-startup>1</load-on-startup>
  </servlet>配在一起试试！！！！

Answer 5

将struts-config-user.xml中的path="/user/userLogin"改为path="/userLogin"这一步做了吗？
你现在的错误好像和web.xml没有关系，应该是struts-config-user.xml中的错误。

Answer 6

问题一样啊，但是我的path=/toUpload，错误提示差不多啊
javax.servlet.ServletException: Cannot retrieve mapping for action /toUpload
.....

Answer 7

想了办法，
1。原来的链接路径是：
index.jsp-->upload/upload.jsp-->/toUpload.do?method=uploadFile-->success.jsp2。现在改成：
index.jsp-->/toUpload.do?method=changePath-->upload/upload.jsp-->/toUpload.do?method=uploadFile-->success.jsp就解决问题了,有点繁琐,当然用switchaction应该可以解决，准备看。
原因可能是:按1，在多模块下index.jsp属于默认模块，而upload.jsp属于upload模块，直接通过<html:link page="/upload/upload.jsp">upload 1</html:link>并没有从默认模块转到upload模块，还是会从默认配置中找，所以，upload.jsp中<html:form action="****">中***是/toUpload,/toUpload.do,/upload/toUpload....等都会报javax.servlet.ServletException: Cannot retrieve mapping for action /toUpload 的异常
按2，index.jsp和upload.jsp通过upload的action转一下，<html:link page="/upload/toUpload.do?method=uploadFile">upload 2</html:link>会从默认模块转到upload模块中，用<html:link module="/upload" action="/toUpload.do?method=uploadFile">upload 2</html:link>可能清晰点

Answer 8

应该是:
<param-name>config/user</param-name>
中
config/user
不能带有'/'符号,用下划线'_'应该好一点

Answer 9

<init-param>
         <param-name>config</param-name>        
         <param-value>/WEB-INF/ht/struts-config.xml,/WEB-INF/ht/struts-config-hy.xml,/WEB-INF/ht/struts-config-fqq.xml</param-value>
      </init-param>

Answer 10

楼上是对的
<init-param>是给个属性装数据，只能是config。struts支持用逗号分开的多个值
如果为了好看，可以用CDATA签
<init-param>
    <param-name>config</param-name>        
    <param-value>
         <![CDATA[
         /WEB-INF/ht/struts-config.xml
        ,/WEB-INF/ht/struts-config-hy.xml
        ,/WEB-INF/ht/struts-config-fqq.xml
        ]]>
    </param-value>
</init-param>

Answer 11

<init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/struts-config.xml,
         /WEB-INF/struts-config-1.xml,
         /WEB-INF/struts-config-2.xml,
         /WEB-INF/struts-config-3.xml
      </param-value>

Answer 12

web.xml
        <init-param>
            <param-name> config </param-name>
            <param-value> /WEB-INF/struts-config.xml </param-value>
        </init-param>    
        <init-param>
            <param-name> config/user </param-name>
            <param-value> /WEB-INF/struts-config-user.xml </param-value>
        </init-param>  
struts-config-user.xml
    <action-mappings   type= "org.apache.struts.action.ActionMapping ">    
          <action
          attribute= "userForm "
          input= "/user/userBas.jsp "
          name= "userForm "
          path= "/insertUser "  
              type= "com.aaa.action.user.StarAction "
              scope= "request "
              validate= "false ">
            <forward
            name= "success "
            contextRelative= "true "
            path= "/star/admin.jsp "   />            
          </action>
    </action-mappings>
userBas.jsp
<form   action= "/insertUser .do "> 
</form>

Answer 13

<form action= "/insertUser.do">
<html:form action= "/insertUser.do">
两者的action是不一样的
struts的html:form在解析成form时,会在原始action前面加入模块名