spring+hibernate的问题？

Question

exception javax.servlet.ServletException
org.apache.struts2.dispatcher.Dispatcher.serviceAction(Dispatcher.java:515)
org.apache.struts2.dispatcher.FilterDispatcher.doFilter(FilterDispatcher.java:419)
org.apache.struts2.dispatcher.ActionContextCleanUp.doFilter(ActionContextCleanUp.java:99)
root cause java.lang.NullPointerException
com.crud.action.UserAction.execute(UserAction.java:48)
sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
java.lang.reflect.Method.invoke(Method.java:585)
com.opensymphony.xwork2.DefaultActionInvocation.invokeAction(DefaultActionInvocation.java:404)
com.opensymphony.xwork2.DefaultActionInvocation.invokeActionOnly(DefaultActionInvocation.java:267)
com.opensymphony.xwork2.DefaultActionInvocation.invoke(DefaultActionInvocation.java:229)
com.opensymphony.xwork2.interceptor.DefaultWorkflowInterceptor.doIntercept(DefaultWorkflowInterceptor.java:221)
com.opensymphony.xwork2.interceptor.MethodFilterInterceptor.intercept(MethodFilterInterceptor.java:86)
com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling(DefaultActionInvocation.java:224)
com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling(DefaultActionInvocation.java:223)
com.opensymphony.xwork2.util.profiling.UtilTimerStack.profile(UtilTimerStack.java:455)
com.opensymphony.xwork2.DefaultActionInvocation.invoke(DefaultActionInvocation.java:221)
com.opensymphony.xwork2.validator.ValidationInterceptor.doIntercept(ValidationInterceptor.java:150)
org.apache.struts2.interceptor.validation.AnnotationValidationInterceptor.doIntercept(AnnotationValidationInterceptor.java:48)
com.opensymphony.xwork2.interceptor.MethodFilterInterceptor.intercept(MethodFilterInterceptor.java:86)
com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling(DefaultActionInvocation.java:224)
com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling(DefaultActionInvocation.java:223)
com.opensymphony.xwork2.util.profiling.UtilTimerStack.profile(UtilTimerStack.java:455)
com.opensymphony.xwork2.DefaultActionInvocation.invoke(DefaultActionInvocation.java:221)
com.opensymphony.xwork2.interceptor.ConversionErrorInterceptor.intercept(ConversionErrorInterceptor.java:123)
com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling(DefaultActionInvocation.java:224)
com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling(DefaultActionInvocation.java:223)
com.opensymphony.xwork2.util.profiling.UtilTimerStack.profile(UtilTimerStack.java:455)
com.opensymphony.xwork2.DefaultActionInvocation.invoke(DefaultActionInvocation.java:221)
com.opensymphony.xwork2.interceptor.ParametersInterceptor.doIntercept(ParametersInterceptor.java:167)
com.opensymphony.xwork2.interceptor.MethodFilterInterceptor.intercept(MethodFilterInterceptor.java:86)
com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling(DefaultActionInvocation.java:224)
com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling

Answer 1

基本上就是这样。还有我的SPRING的配置文件
<?xml version="1.0" encoding="UTF-8"?>
<beans
xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd">
<bean id="dataSource"
class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiName" value="java:comp/env/jdbc/wcd"></property>
</bean>
<!--<bean id="dataSource"
class="org.springframework.jdbc.datasource.UserCredentialsDataSourceAdapter">
<property name="targetDataSource">
<ref bean="dataSourcetarget" />
</property>
<property name="username" value="wang"></property>
<property name="password" value="wangpwd"></property>
</bean>-->
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource">
<ref bean="dataSource" />
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">
org.hibernate.dialect.Oracle9Dialect
</prop>
<prop key="show_sql">true</prop>
</props>
</property>
<property name="mappingResources">
<list>
<value>com/crud/modelBean/Test.hbm.xml</value>
</list>
</property>
</bean>
<bean id="transactionManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory">
<ref bean="sessionFactory"/>
</property>
</bean>

    <bean id="usi" class="com.crud.services.impl.UserServicesImpl">
     <property name="ud" ref="ud"/>
    </bean>
<bean id="ud" class="com.crud.dao.impl.UsersImpl">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
    
</beans>

Answer 2

UserAction.java:48
UserAction.java的48行错，先找到那一行

Answer 3

boolean   flag   =   usi.registUsers(username,   pwd,   address,   truename); 
报的就是这个错，是调用业务逻辑的错误？会不会是配置方面有错呢？
在WEB。XML里我有申明了DATASOURCE了如下：
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" 
xmlns="http://java.sun.com/xml/ns/j2ee" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
  <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>
  
  <filter>
<filter-name>struts2-cleanup</filter-name>
<filter-class>org.apache.struts2.dispatcher.ActionContextCleanUp</filter-class>
  </filter>
  <filter-mapping>
   <filter-name>struts2-cleanup</filter-name>
   <url-pattern>/*</url-pattern>
  </filter-mapping>
  
  <filter>
        <filter-name>struts2</filter-name>
        <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
  </filter>
  <filter-mapping>
   <filter-name>struts2</filter-name>
   <url-pattern>/*</url-pattern>
  </filter-mapping>
  
  <!--<servlet>
<servlet-name>dwr</servlet-name>
<servlet-class>uk.ltd.getahead.dwr.DWRServlet</servlet-class>
<init-param>
<param-name>debug</param-name>
<param-value>true</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>dwr</servlet-name>
<url-pattern>/dwr/*</url-pattern>
</servlet-mapping>
  
  --><resource-ref>
    <description>DataSource test</description>
    <res-ref-name>jdbc/wcd</res-ref-name>
    <res-type>javax.sql.DataSource</res-type>
    <res-auth>Container</res-auth>
  </resource-ref>
  
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
</web-app>

Answer 4

com.crud.action.UserAction.execute(UserAction.java:48) 
UserAction第48行是什么?

Answer 5

boolean flag = usi.registUsers(username, pwd,address,truename); 
就是这一行
是调用的UserServicesImpl里的方法

Answer 6

你Action里面是否注入了你的Service?
也就是说boolean flag = usi.registUsers(username, pwd, address, truename);
中的usi是否已经代理了？   

Answer 7

已经注入了，如何代理，我的SPRING配置文件也在上面？
我的ACTION文件：package com.crud.action;import com.crud.services.impl.UserServicesImpl;
import com.opensymphony.xwork2.ActionSupport;public class UserAction extends ActionSupport {
private UserServicesImpl usi;
private String username;
private String pwd;
private String address;
private String truename;
private String rePwd;
public String getRePwd() {
return rePwd;
}
public void setRePwd(String rePwd) {
this.rePwd = rePwd;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPwd() {
return pwd;
}
public void setPwd(String pwd) {
this.pwd = pwd;
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address;
}
public String getTruename() {
return truename;
}
public void setTruename(String truename) {
this.truename = truename;
}
public void setUsi(UserServicesImpl usi) {
this.usi = usi;
}

public String execute() {
boolean flag = usi.registUsers(username, pwd, address, truename);
System.out.println("**********" + flag);
if (flag == true) {
return SUCCESS;
} else {
addActionError("注册用户名时出错！");
return ERROR;
}
}
}

Answer 8

这里的UserAction中的UserServicesImpl 没有初始化，你应该在Spring的配置文件中给UserAction注入UserServicesImpl或者在UserAction中使用new构造一个UserSerivceImpl

Answer 9

情况1：如果你的UserAction也是由Spring来管理的，那么你只要在配置中给UserAction注入userServicesImpl就可以了
情况2：如果你的UserAction不由Spring管理，那么你需要从BeanFactory中去拿一下这个bean，最好不要去new一个吧

Answer 10

楼主 很搞笑
if（e）
system“我草，出错了”else
system("我草，通过了 ")

Answer 11

楼上的两位朋友，我的SPRING文件也在上面，你看哪里错了，帮我改下好吗？贴在下面，呵呵，SPRING初学
刚才我又把ACTION文件改了下把业务逻辑里的TEST移到ACTION里边实例化直接在ACTION里获取信息也没用。。
但是我action里打印出来的username,password，address和truename全是能获取的！就是boolean   flag   =   usi.registUsers(username,   pwd,   address,   truename); 
出的错可能SPRING没配置好吧，谢谢各位了！

Answer 12

顺便说下我没把struts2集成到SPRING里

Answer 13

“刚才我又把ACTION文件改了下把业务逻辑里的TEST移到ACTION里边实例化直接在ACTION里获取信息也没用。。 ”
我不太明白这句话是什么意思？LZ说一下啊
建议：既然你已经用了Spring，我建议你把Action也用Spring管理好了，这样就可以比较方便的取到注入一些bean，否则话你要用Spring的基本方式，比如
ApplicationContext ctx = new FileSystemXmlApplicationContext("WEB-INF/beans.xml");
TestBean t = (TestBean) ctx.getBean("testBean");
System.out.println(t.sayHello());
来取到一些bean，当然你也可以写个父类，然后继承一下，反正你自己斟酌一下看

Answer 14

哦，我知道了，谢谢楼上的朋友，我把STRUTS2集成到SPRING里去吧，呵呵，比较麻烦，2个配置文件全要写~