怎么把MVC中 service层的对象输出到action中？

Question

ac.getSession().put("Owner", owner);你都注释了 怎么显示
除了表色标注的都可以显示？？那就是查询的问题 或者数据库表中本身没有数据

Answer 1

查询没有问题，那个是在service里面写的
public class OwnerServiceImp implements OwnerService { private EntityDao entityDao;
//业主登陆
public String owner_Login(Owner owner) {
// TODO Auto-generated method stub
System.out.println("进入登录.....");
String view="Tourists";
String hql="from Owner where ownerName='"+owner.getOwnerName()+"' and ownerTel='"+owner.getOwnerTel()+"'";
//强制类型转换
List<Owner> list= find(hql);
if(list.size()>0)
{
view="Owner";
owner=list.get(0);
System.out.println(owner.getOwnerGender()+owner.getOwnerIdcard()+owner.getOwnerRoom()+owner.getOwnerWork());
ActionContext ac=ActionContext.getContext();//保存session，相当于request.getSession().setAttribute("listMessage",listMessage);
System.out.println(owner);
ac.getSession().put("Owner", owner);
}
else{
view = "error";
ActionContext ac=ActionContext.getContext();
ac.getSession().put("errorinfo","业主不存在！");
} return view;
}

//把查找的结果进行强制类型转换
public List<Owner> find(String hql) {
// TODO Auto-generated method stub
List<Owner> list = new ArrayList<Owner>();
for(Object o:entityDao.find(hql)){
list.add((Owner)o);
}
return list;
}



public EntityDao getEntityDao() {
return entityDao;
}
public void setEntityDao(EntityDao entityDao) {
this.entityDao = entityDao;
} public List<Owner> findo(String hql) {
// TODO Auto-generated method stub
List<Owner> list= new ArrayList<Owner>();;
for(Object o:entityDao.find(hql))
{
list.add((Owner)o);
}
return list;
}
}