if(username!=null)可能这个一直为空
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description The server encountered an internal error () that prevented it from fulfilling this request.exception javax.servlet.ServletException
org.apache.struts.action.RequestProcessor.processException(RequestProcessor.java:545)
org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:486)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482)
org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525)
javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause java.lang.NullPointerException
com.presentation.action.SignonAction.execute(SignonAction.java:55)
org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482)
org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525)
javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.5.17 logs.
然后用setString(1,username);
sql="select * from signon where username='"+username+"'";
我把username直接换成
sql="select * from signon where username='abc'";
也还是有这个问题啊~
这句是不是用来建立连接的?连接正常吗?
public ResultSet executeQuery(String sql)
{
try{
conn=DriverManager.getConnection(url, user, password);
stmt=conn.createStatementResultSet.TYPE_SCROLL_SENSITIVE,
ResultSet.CONCUR_READ_ONLY);
stmt.executeQuery(sql);
}
catch(SQLException ex){
System.err.println("Sql_data.executeQuery:"+ex.getMessage());
}
return rs;
}