我想在菜单事件中调用方法.但出错了.

Question

AddUse是向表添加用户
JMenu fileoperation=new JMenu("操作");
JMenuItem fileadd=new JMenuItem("添加");
fileoperation.add(fileadd);
bar.add(fileoperation);fileadd.addActionListener(this);//事件处理
public void actionPerformed(ActionEvent ae) throws Exception
{
String arg=(String)ae.getActionCommand();
if(arg.equals("添加"))
{
int re=AddUse(text1.getText(),text2.getText(),text3.getText(),text4.getText(),text5.getText());
}
}提示:main 中的 actionPerformed(java.awt.event.ActionEvent) 无法实现 java.awt.event.ActionListener 中的 actionPerformed(java.awt.event.ActionEvent)；被覆盖的方法不抛出 java.lang.Exception
        public void actionPerformed(ActionEvent ae) throws Exception如果不添加 throws Exception,又提示:未报告的异常 java.lang.Exception；必须对其进行捕捉或声明以便抛出int re=AddUse(text1.getText(),text2.getText(),text3.getText(),text4.getText(),text5.getText());请指点一下,谢谢

Answer 1

我下面这个就没throws Exception,像沙发说的加try...catch...就好了.
//////////////////////////////////////////////////////////////////public void actionPerformed(ActionEvent e) {
             if (e.getSource() == jme) {
JOptionPane.showMessageDialog(panel, "" + "请在第一个文本框输入网址"
+ " \n（如：www.163.com）" + "\n如该处为空则ping本机IP"
+ "\n                                         2006-11-30");// 实现“关于”按钮 }
             if(e.getSource() == button){
                if(tf1.getText() == null || "".equals(tf1.getText())){
                     try{
                      ia = InetAddress.getLocalHost();
                      s2 = ia.toString().substring(16, 31);
                      
                        loger = Logger.getLogger("testLogger");
                
                   loger.info("localhost/"+s2);
                   loger.info("-------------------------");
                
                      tf2.setText(s2);
                      }
                      catch(Exception e1){
                       System.out.println(e1.getMessage());
                      }
                }else{
                      try{
                      ia = InetAddress.getByName(tf1.getText());
                      
                      loger = Logger.getLogger("testLogger");
              
                 loger.info(ia);
                 loger.info("-------------------------");
                
                      tf2.setText(ia.toString());
                      }
                      catch(Exception e2){
                       System.out.println(e2.getMessage());
                      }
                }
             }
       }

Answer 2

这段代码有可能出现异常，java为了安全起见，要你把这段代码放入到
try
{
}catch()
{
}
语句中，这样如果有错误的话，就会根据catch中的设置打印出什么地方出错了