这个问题分两种情况来讨论 1) public class Test2 { public static void main(String[] args) { Test2 test = new Test2(); test.fun01(); }
public void fun01(){ Vector v = new Vector(); v.add("A1"); v.add("A2"); v.add("A3"); Conica.pl(v);
String vS = v.toString(); } } 如果Vector里面都是字符串的话,那么可以看到输出结果是[A1, A2, A3] 如果要解析回来,可以用这个方法去做: public Vector fun03(String vS) { vS = vS.substring(1, vS.length() - 1);// remove the bracket String[] elements = vS.split(","); Vector v = new Vector(); for (int i = 0; i < elements.length; i++) { if (i == 0) { v.add(elements[i]); continue; } int len = elements[i].length(); String value = elements[i].substring(1, len); // remove the blank before the elements if have; v.add(value); }
return v; } 2) class K { public K(){
} }public class Test2 { public static void main(String[] args) { Test2 test = new Test2(); test.fun01(); }
public void fun01(){ Vector v = new Vector(); K k = new K(); v.add("A1"); v.add("A2"); v.add("A3"); v.add(k); Conica.pl(v);
//-----------------------------------------------------------------------------------
//VectorDemo.java
import java.util.*;public class VectorDemo
{
public static void main(String[] args)
{
Vector v;
String s="I was,I am!"; v=StringToVector.toVector(s);
System.out.println(v.toString());
}}class StringToVector
{
public static Vector toVector(String s)
{
Vector v=new Vector();
for(int i=0;i<s.length();i++)
{
v.add(s.charAt(i));
}
return v;
}
}
是把一个字符串当作整体转为Vector类型呢 还是把String中的每个字符作为Vector的一个元素呢?
String s=v.toString();
v是Vector类型的变量
那反过来应该怎样将s转换成Vector类型?
1)
public class Test2 { public static void main(String[] args) {
Test2 test = new Test2();
test.fun01();
}
public void fun01(){
Vector v = new Vector();
v.add("A1");
v.add("A2");
v.add("A3");
Conica.pl(v);
String vS = v.toString();
}
}
如果Vector里面都是字符串的话,那么可以看到输出结果是[A1, A2, A3]
如果要解析回来,可以用这个方法去做:
public Vector fun03(String vS) {
vS = vS.substring(1, vS.length() - 1);// remove the bracket
String[] elements = vS.split(",");
Vector v = new Vector();
for (int i = 0; i < elements.length; i++) {
if (i == 0) {
v.add(elements[i]);
continue;
}
int len = elements[i].length();
String value = elements[i].substring(1, len); // remove the blank before the elements if have;
v.add(value);
}
return v;
}
2)
class K {
public K(){
}
}public class Test2 { public static void main(String[] args) {
Test2 test = new Test2();
test.fun01();
}
public void fun01(){
Vector v = new Vector();
K k = new K();
v.add("A1");
v.add("A2");
v.add("A3");
v.add(k);
Conica.pl(v);
String vS = v.toString();
}
}
如果是这样,你会看到输出的是
[A1, A2, A3, november.K@d9f9c3]
这样要转的话,恐怕神仙都做不到了,尤其是你在根本不知道K是什么东东的前提下。