import java.io.*;
public class u{
static int t;
public static int f(int n){
if(n<=1) t=1;
else {
f(n)=(f(n-1)+f(n-2));
t=f(n);
}
return t; }public static void main(String args[] ){
int m,p;
u i=new u();
try{m=System.in.read();}catch(Exception e){System.out.println("Exception");}
p=u.f(m);System.out.println(p);
}}
public class u{
static int t;
public static int f(int n){
if(n<=1) t=1;
else {
f(n)=(f(n-1)+f(n-2));
t=f(n);
}
return t; }public static void main(String args[] ){
int m,p;
u i=new u();
try{m=System.in.read();}catch(Exception e){System.out.println("Exception");}
p=u.f(m);System.out.println(p);
}}
import java.io.BufferedReader;
import java.io.InputStreamReader;/*
* 创建日期 2006-9-25
*
* TODO 要更改此生成的文件的模板,请转至
* 窗口 - 首选项 - Java - 代码样式 - 代码模板
*/public class test {
public int f(int n){
if(n<=1)
return 1;
else
return (f(n-1)+f(n-2));
} public static void main(String args[] ){
try{
int m = 0,p = 0;
test i=new test();
BufferedReader ib = new BufferedReader(new InputStreamReader(System.in));
System.out.print("please input:");
String str = ib.readLine();
m=Integer.parseInt(str);
p=i.f(m);
System.out.println("input:" + m + " result:" + p);
}catch(Exception e){
e.printStackTrace();
System.out.println("Exception");
}
}
}
按楼上的来,递归一定要有返回,否则就是死循环
通过键盘输入的数字是string型,要转为int型