怎样写最好?

Question

有一个大于8位的字符串,把后8为取出赋予A,把8为以前赋予B

Answer 1

String str="1234567890";
String a=str.substring(str.length()-8,str.length());
String b=str.substring(0,str.length()-8);

Answer 2

又来晚了,发现treeroot(旗鲁特) 抢沙发特强:)

Answer 3

public class TestString{
public static void main(String[] args){
String s ="987654321";
String A = s.substring(s.length()-8,s.length());
System.out.println("A: "+A);
String B = s.replace(A,"");//把s中A替换为空 就是字符串B
System.out.println("B: "+B);
}
}
/*输出结果
A: 87654321
B: 9
*/

Answer 4

tooooooooooooooooooooooooooooooo lateeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Answer 5

String a=str.substring(str.length()-8,str.length());
String b=str.substring(0,str.length()-8);