struts action类public final class addaction extends Action
{
public ActionForward perform
(ActionMapping mapping,
ActionForm form,
HttpServletRequest request,
HttpServletResponse response)
throws IOException, ServletException
{
return mapping.findForward("success");
}
}struts-config.xml <struts-config>
<!-- ======================================== data-sources definitions --><!-- ======================================== Form Bean Definitions --> <form-beans>
<form-bean
name="addForm"
type="app.addform"/>
</form-beans>
<!-- =================================== Global Forward Definitions --><!-- =================================== Action Mapping Definitions --> <action-mappings> <action
path="/error"
type="org.apache.struts.actions.ForwardAction"
parameter="/error.jsp"/>
<action
path="/add"
type="app.addaction"
scope="request">
<forward name="success" path="/success.jsp" />
<forward name="error" path="/error.do" />
</action>
</action-mappings></struts-config>提交到/add.do的时候页面就不动了 为什么没有跳转到success.jsp
谁教我 各位大哥 帮帮忙啊
{
public ActionForward perform
(ActionMapping mapping,
ActionForm form,
HttpServletRequest request,
HttpServletResponse response)
throws IOException, ServletException
{
return mapping.findForward("success");
}
}struts-config.xml <struts-config>
<!-- ======================================== data-sources definitions --><!-- ======================================== Form Bean Definitions --> <form-beans>
<form-bean
name="addForm"
type="app.addform"/>
</form-beans>
<!-- =================================== Global Forward Definitions --><!-- =================================== Action Mapping Definitions --> <action-mappings> <action
path="/error"
type="org.apache.struts.actions.ForwardAction"
parameter="/error.jsp"/>
<action
path="/add"
type="app.addaction"
scope="request">
<forward name="success" path="/success.jsp" />
<forward name="error" path="/error.do" />
</action>
</action-mappings></struts-config>提交到/add.do的时候页面就不动了 为什么没有跳转到success.jsp
谁教我 各位大哥 帮帮忙啊
另外把你的action的perform方法改成execute();
----〉重新部署tomcat,重启!
System.out.println("程序进入action");
try{
//code
}catch(Exception e){
e.printStackTrace;
}