SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat formatter = new SimpleDateFormat ("yyyy-MM-dd '' HH:mm:ss"); Date currentTime_1 = new Date(); String dateString = formatter.format(currentTime_1);
取10天前Calendar cld = Calendar.getInstance(); int year = cld.get(Calendar.YEAR); int month = cld.get(Calendar.MONTH); int day = cld.get(Calendar.DAY_OF_MONTH); cld.add(Calendar.DAY_OF_MONTH,-10); String date = year + "-" + (month + 1) + "-" + day;
java.text.SimpleDateFormat formatter = new java.text.SimpleDateFormat ("yyyy-MM-dd '' HH:mm:ss");
java.text.SimpleDateFormat formatter = new java.text.SimpleDateFormat ("yy-MM-dd '' HH:mm:ss");yy,MM,HH都是可以修改的, 包括长度和顺序
package com.infoearth;import java.sql.Timestamp; import java.text.*; import java.util.*; /** * @lcl * public class ManageWeek { //判断两个日期是否在同一周 boolean isSameWeekDates(Date date1, Date date2) { Calendar cal1 = Calendar.getInstance(); Calendar cal2 = Calendar.getInstance(); cal1.setTime(date1); cal2.setTime(date2); int subYear = cal1.get(Calendar.YEAR) - cal2.get(Calendar.YEAR); if (0 == subYear) { if (cal1.get(Calendar.WEEK_OF_YEAR) == cal2.get(Calendar.WEEK_OF_YEAR)) return true; } else if (1 == subYear && 11 == cal2.get(Calendar.MONTH)) { // 如果12月的最后一周横跨来年第一周的话则最后一周即算做来年的第一周 if (cal1.get(Calendar.WEEK_OF_YEAR) == cal2.get(Calendar.WEEK_OF_YEAR)) return true; } else if (-1 == subYear && 11 == cal1.get(Calendar.MONTH)) { if (cal1.get(Calendar.WEEK_OF_YEAR) == cal2.get(Calendar.WEEK_OF_YEAR)) return true; } return false; }
//产生周序列 public static String getSeqWeek(){ Calendar c = Calendar.getInstance(Locale.CHINA); String week = Integer.toString(c.get(Calendar.WEEK_OF_YEAR)); if(week.length()==1)week = "0" + week; String year = Integer.toString(c.get(Calendar.YEAR)); return year+week;
}
//获得周一的日期 public static String getMonday(Date date){ Calendar c = Calendar.getInstance(); c.setTime(date); c.set(Calendar.DAY_OF_WEEK,Calendar.MONDAY); return new SimpleDateFormat("yyyy-MM-dd").format(c.getTime()); }
//获得周五的日期 public static String getFriday(Date date){ Calendar c = Calendar.getInstance(); c.setTime(date); c.set(Calendar.DAY_OF_WEEK,Calendar.FRIDAY); return new SimpleDateFormat("yyyy-MM-dd").format(c.getTime()); }//当前日期前几天或者后几天的日期 public static String afterNDay(int n){ Calendar c=Calendar.getInstance(); DateFormat df=new SimpleDateFormat("yyyy-MM-dd"); c.setTime(new Date()); c.add(Calendar.DATE,n); Date d2=c.getTime(); String s=df.format(d2); return s; }
public static void main(String[] args){ }} 经常碰到把一个字符串转成一个Date的问题,其实就3句话:String myString = "2005/12/20";SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/dd", Locale.CHINA); Date d = sdf.parse(myString);下面是个例子,存档 package formatdatetime;import java.text.*; import java.util.*;/** * @author Administrator * * TODO 要更改此生成的类型注释的模板,请转至 * 窗口 - 首选项 - Java - 代码样式 - 代码模板 */ public class StringToDateTimeTest { public static void main(String[] args) { String myString = "Tue Oct 18 04:11:56 CST 2005"; //String myString = "2005/12/20"; try { SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US); //SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/dd", Locale.CHINA); Date d = sdf.parse(myString); Calendar c = Calendar.getInstance(); c.setTime(d); String s = new SimpleDateFormat("yyyy-MM-dd").format(c.getTime()); System.out.println(s);
int year = cld.get(Calendar.YEAR);
int month = cld.get(Calendar.MONTH);
int day = cld.get(Calendar.DAY_OF_MONTH);
cld.add(Calendar.DAY_OF_MONTH,-10);
String date = year + "-" + (month + 1) + "-" + day;
import java.text.*;
import java.util.*;
/**
* @lcl
*
public class ManageWeek {
//判断两个日期是否在同一周
boolean isSameWeekDates(Date date1, Date date2) {
Calendar cal1 = Calendar.getInstance();
Calendar cal2 = Calendar.getInstance();
cal1.setTime(date1);
cal2.setTime(date2);
int subYear = cal1.get(Calendar.YEAR) - cal2.get(Calendar.YEAR);
if (0 == subYear) {
if (cal1.get(Calendar.WEEK_OF_YEAR) == cal2.get(Calendar.WEEK_OF_YEAR))
return true;
}
else if (1 == subYear && 11 == cal2.get(Calendar.MONTH)) {
// 如果12月的最后一周横跨来年第一周的话则最后一周即算做来年的第一周
if (cal1.get(Calendar.WEEK_OF_YEAR) == cal2.get(Calendar.WEEK_OF_YEAR))
return true;
}
else if (-1 == subYear && 11 == cal1.get(Calendar.MONTH)) {
if (cal1.get(Calendar.WEEK_OF_YEAR) == cal2.get(Calendar.WEEK_OF_YEAR))
return true;
}
return false;
}
//产生周序列
public static String getSeqWeek(){
Calendar c = Calendar.getInstance(Locale.CHINA);
String week = Integer.toString(c.get(Calendar.WEEK_OF_YEAR));
if(week.length()==1)week = "0" + week;
String year = Integer.toString(c.get(Calendar.YEAR));
return year+week;
}
//获得周一的日期
public static String getMonday(Date date){
Calendar c = Calendar.getInstance();
c.setTime(date);
c.set(Calendar.DAY_OF_WEEK,Calendar.MONDAY);
return new SimpleDateFormat("yyyy-MM-dd").format(c.getTime());
}
//获得周五的日期
public static String getFriday(Date date){
Calendar c = Calendar.getInstance();
c.setTime(date);
c.set(Calendar.DAY_OF_WEEK,Calendar.FRIDAY);
return new SimpleDateFormat("yyyy-MM-dd").format(c.getTime());
}//当前日期前几天或者后几天的日期 public static String afterNDay(int n){
Calendar c=Calendar.getInstance();
DateFormat df=new SimpleDateFormat("yyyy-MM-dd");
c.setTime(new Date());
c.add(Calendar.DATE,n);
Date d2=c.getTime();
String s=df.format(d2);
return s;
}
public static void main(String[] args){ }}
经常碰到把一个字符串转成一个Date的问题,其实就3句话:String myString = "2005/12/20";SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/dd", Locale.CHINA);
Date d = sdf.parse(myString);下面是个例子,存档
package formatdatetime;import java.text.*;
import java.util.*;/**
* @author Administrator
*
* TODO 要更改此生成的类型注释的模板,请转至
* 窗口 - 首选项 - Java - 代码样式 - 代码模板
*/
public class StringToDateTimeTest { public static void main(String[] args) { String myString = "Tue Oct 18 04:11:56 CST 2005";
//String myString = "2005/12/20";
try {
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
//SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/dd", Locale.CHINA);
Date d = sdf.parse(myString);
Calendar c = Calendar.getInstance();
c.setTime(d);
String s = new SimpleDateFormat("yyyy-MM-dd").format(c.getTime());
System.out.println(s);
} catch (Exception e) {
e.printStackTrace();
}
}
}