if (password1.equals(password2)) {

return mapping.findForward("success");
}
else{
return mapping.findForward("failure");
}哪位大侠帮我看看,这样写对不对?

解决方案 »

  1.   

    至少先判断password1是否为空,
    if (password1 != null && password1.equals(password2)) {...}
      

  2.   

    package app;import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;import org.apache.struts.action.Action;
    import org.apache.struts.action.ActionForm;
    import org.apache.struts.action.ActionForward;
    import org.apache.struts.action.ActionMapping;import app.RegisterForm;public class RegisterAction extends Action {
    public ActionForward excute (ActionMapping mapping,ActionForm form,HttpServletRequest request,HttpServletResponse response) {
    RegisterForm registerForm=(RegisterForm)form;
    String username = registerForm.getUsername();
    String password1 = registerForm.getPassword1();
    String password2 = registerForm.getPassword2(); if (password1.equals(password2)) {


    return mapping.findForward("success");
    }



    return mapping.findForward("failure");
    }
    }
    这个是STRUTS的RegisterAction.总出现语法错误.
      

  3.   

    就是做Register注册.如果password1和password2相同就注册成功返回success.html否则返回failure.html.总出错.帮解答.
      

  4.   

    这个是register页面。
    <%@ page contentType="text/html; charset=gb2312" language="java" import="java.sql.*" errorPage="" %>
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
    <title>register</title>
    </head><body>
    <form action="register.do" method="get">
    username<input type="text" name="username"><p>
    password1<input type="password" name="password1"><p>
    password2<input type="password" name="password2"><p>
    <input name="register" type="submit" value="Register" />
    </body>
    </html>这个是STRUTS-CONFIG.XML
    <?xml version="1.0" encoding="ISO-8859-1" ?>
    <!DOCTYPE struts-config PUBLIC
    "-//Apache Software Foundation//DTD Struts Configuration 1.0//EN"
    "http://jakarta.apache.org/struts/dtds/struts-config_1_0.dtd">
    <struts-config>
    <form-beans>
    <form-bean name="registerForm" type="app.RegisterForm"/>
    </form-beans>
    <action-mappings>
    <action path="/register.do"
    type="app.RegisterAction"
    name="registerForm">
    <forward name="success" path="/success.html"/>
    <forward name="failure" path="/failure.html"/>
    </action>
    </action-mappings>
    </struts-config>
    这个是WEB.XML(好象不对。帮我看看)<?xml version="1.0" encoding="UTF-8"?>
    <!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "http://java.sun.com/dtd/web-app_2_3.dtd">
    <web-app id="WebApp_ID">
      <display-name>st</display-name>
       <servlet>
        <servlet-name>action</servlet-name>
        <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
        <init-param>
          <param-name>config</param-name>
          <param-value>/WEB-INF/struts-config.xml</param-value>
        </init-param>
        
        <init-param>
          <param-name>debug</param-name>
          <param-value>2</param-value>
        </init-param>
        <load-on-startup>2</load-on-startup>
      </servlet>
      
     
      <servlet-mapping>
        <servlet-name>action</servlet-name>
        <url-pattern>*.do</url-pattern>
      </servlet-mapping>
      <welcome-file-list>
       <welcome-file>register.jsp</welcome-file>
      
      </welcome-file-list>
      
    </web-app>
      

  5.   

    我觉得你先要用try{}catch(){}语句块包含起来,就可以看到是什么错误了嘛