已知字串内容第一行为#打头第二行也为#打头,如-------------------------------------------------
#4234324324
#kkkkkkk
fasdf
fs
daf
sdffasdfasdfsdffasdf
-------------------------------------------------现在求个方法,能最快的删除第二行(就是例子中的 #kkkkkkk)
#4234324324
#kkkkkkk
fasdf
fs
daf
sdffasdfasdfsdffasdf
-------------------------------------------------现在求个方法,能最快的删除第二行(就是例子中的 #kkkkkkk)
return str.substring(0,i)+str.substring(i+1)
public static void main(String args[]){
String str = "#4234324324\n#kkkkkkk\nfasdf\nfs\ndaf\nsdf\nfasdfasdfsdf\nfasdf";
int i = str.indexOf("#",1);
str = str.substring(0,i)+str.replaceAll("#.+\\n","");
System.out.println(str);
}
}
#4234324324
fasdf
fs
daf
sdf
fasdfasdfsdf
fasdf