实现Socket的通讯，应该怎么做？小女子，TAI各位了。

Question

怎么向服务器发送消息。
谁能给我看看：
客户端：
public void startConnect() 
{
  try
  {
   Socket sock=new Socket("127.0.0.1",1001);   if(sock!=null) //connection successed
   {
    processMsg("Connect successfully!");
   }
    out=new PrintWriter(sock.getOutputStream());    in=new BufferedReader(new InputStreamReader(sock.getInputStream()));  }
  catch(IOException ex)
  {
   processMsg(ex.toString());
   processMsg("Connect failed!");
  }
  
  readThread1=new Thread(this);
  readThread1.start();  } public void run()
{
  String msg;
  isTrue=true;
  while(isTrue)
  {
   try
   {
    msg=in.readLine();
    if(msg.equals("Server exit!"))  //server exit
{
     processMsg(msg);
     stopRun();//终止线程
    }
else if(msg!=null)
{
     processMsg(msg);
    }
    Thread.sleep(1000);    
   }
   catch(IOException e)
   {
    processMsg(e.toString());
   }
   catch(InterruptedException ei)
   {
    processMsg(ei.toString());
   }
  }
  //endConnect();
  try  //服务器退出关闭连接和相关的"流"
  {
   sock.close();
   in.close();
   out.close();
  }catch(IOException ioe){} 
 }
}

Answer 1

public static void sendMessage(String theUrl, String content) {    try {
      URL url = new URL(theUrl);
      InetAddress address = InetAddress.getByName(url.getHost());
      Socket client = new Socket(address,
                                 url.getPort() == -1 ? 80 : url.getPort());
      BufferedOutputStream sender = new BufferedOutputStream(client.
          getOutputStream());      String cmd = "POST " + getURLFormat(url) + " HTTP/1.0\r\n" +
          "User-Agent: myselfHttp/1.0\r\n" +
          "Accept: www/source; text/html; image/gif;\r\n";
      cmd += "Content-type: application/x-www-form-urlencoded\r\n";
      cmd += "Content-length: " + content.length() + "\r\n\r\n";
      cmd += content + "\r\n";
      sender.write(cmd.getBytes(), 0, cmd.length());
      sender.flush();
      client.close();
    }
    catch (UnknownHostException ex) {
      ex.printStackTrace();
    }
    catch (MalformedURLException ex) {
      ex.printStackTrace();
    }
    catch (IOException ex) {
      ex.printStackTrace();
    }  }  /****************************************************************************
   *
   * @param target URL
   * @return String
   ****************************************************************************/
  private static String getURLFormat(URL target) {    String spec = "http://" + target.getHost();
    if (target.getPort() != -1){
      spec += ":" + target.getPort();
    }    return spec += target.getFile();
  }

Answer 2

直接调用sendMessage这个方法，把url和你要传的参数传进去就行了。