我的想法是
private InputStream folder;
private AudioStream mic;//////////////////////try
{
folder=new FileInputStream ("folder.wav");
as= new AudioStream (folder);
} catch(IOException e) {
System.out.print("error");
}////////////////////////////////
if (e.getSource()==B10)
{
AudioPlayer.player.start (as); }
/////////////////////////////////
其中总有IOException 该怎么办?
private InputStream folder;
private AudioStream mic;//////////////////////try
{
folder=new FileInputStream ("folder.wav");
as= new AudioStream (folder);
} catch(IOException e) {
System.out.print("error");
}////////////////////////////////
if (e.getSource()==B10)
{
AudioPlayer.player.start (as); }
/////////////////////////////////
其中总有IOException 该怎么办?
import java.net.*;public class WavePlayer { java.applet.AudioClip clip;
URL url;
File file; boolean play(String waveFileName) {
try {
file = new File("d:\\tmp\\test.wav");
if(!file.exists()) {
return false;
}
url = new URL("file:///D:/tmp/test.wav");
clip = java.applet.Applet.newAudioClip(url);
clip.play();
System.out.println("Play : " + waveFileName);
} catch (Exception e) {
e.printStackTrace(System.err);
return false;
}
return true;
}
}
我搜索到的可怎么还是不可以! 在线等待 ! 愿给100分 不够还加 !