紧急问题！JAVA高手帮顶啊！跪谢！

Question

带有命名空间的XML文件如下：
<?xml version="1.0" encoding="Shift_JIS"?><manifest identifier="MANIFEST" version="1.0"
    xmlns="http://www.imsproject.org/xsd/imscp_rootv1p1p2"
    xmlns:adlcp="http://www.adlnet.org/xsd/adlcp_rootv1p2"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.imsglobal.org/xsd/imscp_rootv1p1p2 imscp_rootv1p1p2.xsd
        http://www.imsglobal.org/xsd/imsmd_rootv1p2p1 imsmd_rootv1p2p1.xsd
        http://www.adlnet.org/xsd/adlcp_rootv1p2 adlcp_rootv1p2.xsd">
<metadata>
</metadata>
<organizations default="DreamNetu_SCO">
<organization identifier="DreamNetu_SCO">
<title>Java</title>
<item identifier="DreamNetu_SCO1" identifierref="Res_SCO1" isvisible="true">
<title>Java</title>
</item>
</organization>
</organizations>
<resources>
<resource identifier="Res_SCO1" type="webcontent" adlcp:scormtype="sco" href="lecture.html">
<file href="lecture.html">
</file>
</resource>
</resources>
</manifest> 我在JAVA中如下解析：
HashMap resources = new HashMap();
File file = readFile("e:\2.xml");
Element manifest = document.getRootElement();
List list = manifest.selectNodes("resources/resource");
可是却读不出来节点的信息！
请问在JAVA中该怎样解析？selectNodes方法是否也要加命名空间？该怎样加？最好写个详细的例子！小弟不胜感激！分不是问题！

Answer 1

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(new File("e:/2.xml"));
Element rootElement = document.getDocumentElement();
NodeList list = rootElement.getElementsByTagName("resources");

Answer 2

package canyin;import javax.xml.parsers.*;
import javax.xml.transform.*;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.*;public class connXmlBean {

private DocumentBuilderFactory factory=null;
private DocumentBuilder builder=null;
private Document doc=null;

public connXmlBean(){}

public String connXml(String xmlFileName){

String strExc="";

try{
factory = DocumentBuilderFactory.newInstance();
     builder=factory.newDocumentBuilder();
     doc=builder.parse(xmlFileName);
     doc.normalize();
     }catch(Exception e){
     strExc=e.toString();
   }
  
   return(strExc);
}

public Document getXmlDoc(){
   return(doc);
}
}