java applet怎么与 host:aarondai,port:345的计算机上C#写的监听程序通信？

Question

以下是用c#写的监听程序，怎么写对应的java客户端？
TcpListener tcplsner=new TcpListener(345);
TcpClient tcpClient;
tcplsner.Start();
tcpClient=tcplsner.AcceptTcpClient();
NetworkStream ntStream=tcpClient.GetStream(); string _filePath=txtPath.Text;
FileStream fs = new FileStream(_filePath, FileMode.Open,FileAccess.Read);
int bufferSize;
byte[] buffer = new byte[1024];
progressBar1.Minimum=0;
progressBar1.Value=0;
progressBar1.Maximum=Convert.ToInt32(fs.Length);
while((bufferSize=fs.Read(buffer,0,buffer.GetUpperBound(0)))>0)
{
ntStream.Write(buffer,0,bufferSize);
ntStream.Flush();
try
{
progressBar1.Value+=bufferSize;
}
catch
{
}
System.Windows.Forms.Application.DoEvents();
}
fs.Close();
ntStream.Close();
tcplsner.Stop();

Answer 1

Socket sock=new Socket(InetAddress.getByName("主机地址"),345);
InputStream in=sock.getInputStream();
File file=new File("文件名");
FileOutputStream fout=new FileOutputStream(file);
byte[] bytes=new byte[1024];
int len;
while((len=in.read(bytes))>0)
    fout.write(bytes,0.len);
fout.close();
sock.close();