Hibernate之id生成策略

Question

  最近学习Hibernate是借助某个视频教程，提到id生成策略系列的xml配置，然后在设置<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
        "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
        "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"><hibernate-mapping package="com.hibernate">
<class name = "Students" >
<id name = "id">
<generator class = "uuid"></generator>
</id>
<property name="name"></property>
</class>
</hibernate-mapping> 会自动根据配置生成一张表，不知道我要不要把另外几段代码贴出来。
但是提示的是无法插入，没表。视频上就也看到了自动生成表，各种泪奔
求解释~谢谢！！HibernateXML

Answer 1

其实那个问题解决了，但是这里有个新问题package com.hibernate.second;import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.SequenceGenerator;
import javax.persistence.Table;import org.hibernate.annotations.GenericGenerator; @Entity
@SequenceGenerator(name="workerSEQ",sequenceName="workerSEQ_DB")
public class Worker {
private int salary;
private String name;
private int age;

@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE,generator = "WorkerSEQ")
public int getSalary() {
return salary;
}
public void setSalary(int salary) {
this.salary = salary;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}

}
报的错：Exception in thread "main" org.hibernate.AnnotationException: Unknown Id.generator: WorkerSEQ
at org.hibernate.cfg.BinderHelper.makeIdGenerator(BinderHelper.java:428)
at org.hibernate.cfg.AnnotationBinder.bindId(AnnotationBinder.java:1901)
at org.hibernate.cfg.AnnotationBinder.processElementAnnotations(AnnotationBinder.java:1279)
at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:754)
at org.hibernate.cfg.AnnotationConfiguration.processArtifactsOfType(AnnotationConfiguration.java:546)
at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:291)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1319)
at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:867)
at WorkerTest.main(WorkerTest.java:17)
求指导，谢谢！

Answer 2

反对法package com.hibernate.second;
 
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.SequenceGenerator;
import javax.persistence.Table;
 
import org.hibernate.annotations.GenericGenerator;
 
    @Entity
    @SequenceGenerator(name="workerSEQ",sequenceName="workerSEQ_DB")
    public class Worker {
    private int salary;
    private String name;
    private int age;
     
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE,generator = "WorkerSEQ")
    public int getSalary() {
        return salary;
    }
    public void setSalary(int salary) {
        this.salary = salary;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public int getAge() {
        return age;
    }
    public void setAge(int age) {
        this.age = age;
    }
     
}
报的错：Exception in thread "main" org.hibernate.AnnotationException: Unknown Id.generator: WorkerSEQ
at org.hibernate.cfg.BinderHelper.makeIdGenerator(BinderHelper.java:428)
at org.hibernate.cfg.AnnotationBinder.bindId(AnnotationBinder.java:1901)
at org.hibernate.cfg.AnnotationBinder.processElementAnnotations(AnnotationBinder.java:1279)
at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:754)
at org.hibernate.cfg.AnnotationConfiguration.processArtifactsOfType(AnnotationConfiguration.java:546)
at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:291)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1319)
at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:867)
at WorkerTest.main(WorkerTest.java:17)
求指导，谢谢！