急,求救!!!!在线等待!!!!!!!!! 同意Squall1009(钰枫)(向程序员们靠拢)已经说的很详细了! 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 同意Squall1009(钰枫)(向程序员们靠拢)已经说的很详细了!楼主应该可以写出程序了吧!如果这样也不行,你就转行算了.多多向高手们学习.帮你顶一顶. 按照“Squall1009(钰枫)(向程序员们靠拢)”的思路写的:public class Conversion { public static double conversion(double init){ return init*60; } public static void main(String[] args) { double init = 120.73; System.out.println("转换前"+init+"度"); double fen = conversion(init - (int)init); double miao = conversion(fen-(int)fen); System.out.println("转换后"+(int)init+"度"+(int)fen+"分"+(int)miao+"秒"); }} 我晕,这种问题也能上csdn,楼主你懒得也太厉害了吧 以下使我写的程序:::import java.io.*;import java.lang.Math ;import java.lang.Double ;import java.util.StringTokenizer;public class Deg { public String ldegree,sxinteg ,decim,dufenmiao; public String Deg(String degree){ if ( degree ==null){ System.out.println("请输入一个有效的数字字符串"); return null; } this.ldegree = degree ; StringTokenizer st = new StringTokenizer(ldegree,"."); sxinteg = st.nextToken(); double dinteg ; //判断是否为有效字符 try{ dinteg=Double.parseDouble(sxinteg); } catch(NumberFormatException ehr){ System.err.println("Unable to parse: "+sxinteg); return null;} if (st.hasMoreTokens()){ decim = st.nextToken(); } else { dufenmiao=sxinteg; System.out.println(dufenmiao); return dufenmiao ;} // 取得整数度 decim="0."+decim; double xint,xfen,xmiao; try{xfen=Double.parseDouble(decim); } ////判断是否为有效字符 catch(NumberFormatException ehr){ System.err.println("Unable to parse: "+decim); return null;} xint = xfen*60; String sxfen=Double.toString(xint); //取得“分“ String sfen,smiao; StringTokenizer st2 = new StringTokenizer(sxfen,"."); sfen= st2.nextToken(); smiao= st2.nextToken(); if (smiao == null||smiao=="0" ){return sxinteg+"."+sfen ;} smiao="0."+smiao; double dmiao= Double.parseDouble(smiao); dmiao=Math.round(dmiao*60.0); String sxmiao ; sxmiao=Double.toString(dmiao); // 取得“秒“ sxfen=sxfen.substring(0,2); sxmiao=sxmiao.substring(0,2); dufenmiao= sxinteg +"."+sfen+"`"+sxmiao+"``"; System.out.println(dufenmiao); return dufenmiao; } static public void main(String[] args) { String name = args[0]; Deg con =new Deg(); con.Deg(name); }} 以下是我老板程序,大家看看那个好???public class ParserDll{ /** * @param String 要转换的字符串 * @return String 返回度°分′秒″ */ public String getCoordinate(String param){ //System.out.println("param="+param); if (param==null || !checkNum(param)){ System.out.println("参数为空或不是有效的数字字符串!"); return null; } String degree=null,minute=null; String[] store=null; if(param.indexOf(".")>=0){ store=param.split("\\."); }else{ store=new String[1]; store[0]=param; } if (store.length ==2){ minute=getMinute(store[1]); if(minute!=null){ degree=store[0]+"°"+minute; }else{ degree=store[0]+"°"; } }else{ degree=store[0]+"°"; } System.out.println(degree); return degree; } /** *给定字符获得分的信息 * @param min String * @return String */ private String getMinute(String min){ if (min==null){ return null; } String temp=null; String mins=null,secs=null; float fmin=Float.parseFloat("0."+min)*60; String[] store=null; if (fmin>0){ temp=Float.toString(fmin); if (temp.indexOf(".")>=0){ store=temp.split("\\."); if (store.length ==2) secs=getSecond(store[1]); }else{ store=new String[1]; store[0]=temp; } mins=store[0]+"′"; } if (secs!=null){ temp=mins+secs; }else{ temp=mins; } return temp; } /** * 给定字符串获得秒的信息 * @param sec * @return */ private String getSecond(String sec){ if (sec==null){ return null; } float fsec=Float.parseFloat("0."+sec)*60; int second=Math.round(fsec); String temp=null; if (second >0){ temp=Integer.toString(second)+"″"; } return temp; } /** * 检测输入的字符串是否有效 * @param parm String * @return boolean */ private boolean checkNum(String parm){ String numbers="0123456789."; int dot=0; //判断是否包含dot char char chars; for(int i=0;i<parm.length();i++){ chars=parm.charAt(i); if(numbers.indexOf(chars)==-1){ return false; }else if(chars=='.'){ ++dot; if (dot>1){ return false; } } } return true; } public static void main(String[] args) { /* String name = args[0]; ParserDll con =new ParserDll(); con.getCoordinate(name);*/ }} 关于数组的分配 eclipse编译运行文件出现Error: Could not find main class hw8.HuffMain split 问题?急 【求助】啊,谁写过向彩信猫发送文件的程序吗? 用java做的棋盘覆盖问题!不成功!在线急等 JScrollPane 里面不能动态的添加多个CheckBox吗? java目前比较热门的技术 请高手指点 jdk1.3是怎样安装的 怎么样将C语言中的long*转换为JAVA中的long[]? java一个数组排序问题:求若干个数中第k个最大者 一个小问题(关于xml文件的生成) 高分通缉:jdbc为什么不提供getrows的方法!
return init*60;
}
public static void main(String[] args) {
double init = 120.73;
System.out.println("转换前"+init+"度");
double fen = conversion(init - (int)init);
double miao = conversion(fen-(int)fen);
System.out.println("转换后"+(int)init+"度"+(int)fen+"分"+(int)miao+"秒");
}
}
import java.io.*;
import java.lang.Math ;
import java.lang.Double ;
import java.util.StringTokenizer;
public class Deg {
public String ldegree,sxinteg ,decim,dufenmiao;
public String Deg(String degree){
if ( degree ==null){
System.out.println("请输入一个有效的数字字符串");
return null;
}
this.ldegree = degree ;
StringTokenizer st = new StringTokenizer(ldegree,".");
sxinteg = st.nextToken();
double dinteg ;
//判断是否为有效字符
try{ dinteg=Double.parseDouble(sxinteg); }
catch(NumberFormatException ehr){
System.err.println("Unable to parse: "+sxinteg);
return null;}
if (st.hasMoreTokens()){
decim = st.nextToken();
}
else { dufenmiao=sxinteg;
System.out.println(dufenmiao);
return dufenmiao ;}
// 取得整数度
decim="0."+decim;
double xint,xfen,xmiao;
try{xfen=Double.parseDouble(decim); }
////判断是否为有效字符
catch(NumberFormatException ehr){
System.err.println("Unable to parse: "+decim);
return null;}
xint = xfen*60;
String sxfen=Double.toString(xint);
//取得“分“
String sfen,smiao;
StringTokenizer st2 = new StringTokenizer(sxfen,".");
sfen= st2.nextToken();
smiao= st2.nextToken();
if (smiao == null||smiao=="0" ){return sxinteg+"."+sfen ;}
smiao="0."+smiao;
double dmiao= Double.parseDouble(smiao);
dmiao=Math.round(dmiao*60.0);
String sxmiao ;
sxmiao=Double.toString(dmiao);
// 取得“秒“
sxfen=sxfen.substring(0,2);
sxmiao=sxmiao.substring(0,2);
dufenmiao= sxinteg +"."+sfen+"`"+sxmiao+"``";
System.out.println(dufenmiao);
return dufenmiao;
}
static public void main(String[] args) {
String name = args[0];
Deg con =new Deg();
con.Deg(name);
}
}
public class ParserDll{
/**
* @param String 要转换的字符串
* @return String 返回度°分′秒″
*/
public String getCoordinate(String param){
//System.out.println("param="+param);
if (param==null || !checkNum(param)){
System.out.println("参数为空或不是有效的数字字符串!");
return null;
}
String degree=null,minute=null;
String[] store=null;
if(param.indexOf(".")>=0){
store=param.split("\\.");
}else{
store=new String[1];
store[0]=param;
}
if (store.length ==2){
minute=getMinute(store[1]);
if(minute!=null){
degree=store[0]+"°"+minute;
}else{
degree=store[0]+"°";
}
}else{
degree=store[0]+"°";
}
System.out.println(degree);
return degree;
}
/**
*给定字符获得分的信息
* @param min String
* @return String
*/
private String getMinute(String min){
if (min==null){
return null;
}
String temp=null;
String mins=null,secs=null;
float fmin=Float.parseFloat("0."+min)*60;
String[] store=null;
if (fmin>0){
temp=Float.toString(fmin);
if (temp.indexOf(".")>=0){
store=temp.split("\\.");
if (store.length ==2)
secs=getSecond(store[1]);
}else{
store=new String[1];
store[0]=temp;
}
mins=store[0]+"′";
}
if (secs!=null){
temp=mins+secs;
}else{
temp=mins;
}
return temp;
}
/**
* 给定字符串获得秒的信息
* @param sec
* @return
*/
private String getSecond(String sec){
if (sec==null){
return null;
}
float fsec=Float.parseFloat("0."+sec)*60;
int second=Math.round(fsec);
String temp=null;
if (second >0){
temp=Integer.toString(second)+"″";
}
return temp;
}
/**
* 检测输入的字符串是否有效
* @param parm String
* @return boolean
*/
private boolean checkNum(String parm){
String numbers="0123456789.";
int dot=0;
//判断是否包含dot char
char chars;
for(int i=0;i<parm.length();i++){
chars=parm.charAt(i);
if(numbers.indexOf(chars)==-1){
return false;
}else if(chars=='.'){
++dot;
if (dot>1){
return false;
}
}
}
return true;
}
public static void main(String[] args) {
/* String name = args[0];
ParserDll con =new ParserDll();
con.getCoordinate(name);*/
}
}