public class Test { public static void main(String[] args) { String s = "loop1: hello world!\nloop2: hello!\n\nloop34234:234loop23423:32234"; System.out.println("SOURCE:\n"+s+"\nTARGET:\n"); String[] result = s.split("[\n]*loop[0-9]{1,}:"); for(int i=0;i<result.length;i++){ System.out.println(result[i]); } } } 注意:分隔出来的result[0]无用!
s = "loop1: hello world! loop2: hello!"
Vector mystr=new Vector();
i = 0;
pos1 = 0;
pos2 = 0;
while(pos1 = s.indexof("loop",i)
{
i++;
if (s.subString(pos+1,1)>0 && s.subString(pos+1,1)<9)
{
pos2 = s.indexof("loop",i);
mystr.add(s.subString(pos1,pos2);
}
}
不一定对,一个思路。
例如Pattern, PatternMatcher对象详看别人写的文章:
http://dev.csdn.net/article/30/30807.shtm
public static void main(String[] args) {
String s = "loop1: hello world!\nloop2: hello!\n\nloop34234:234loop23423:32234";
System.out.println("SOURCE:\n"+s+"\nTARGET:\n");
String[] result = s.split("[\n]*loop[0-9]{1,}:");
for(int i=0;i<result.length;i++){
System.out.println(result[i]);
}
}
}
注意:分隔出来的result[0]无用!