本帖最后由 zmjfanfan 于 2013-06-19 10:24:44 编辑

解决方案 »

  1.   

    http://bbs.csdn.net/topics/390022377
      

  2.   

    这样看看:
    var a = {"CODE":{"ERROR_CODE":0},"DATA":[{"bj":"初11级02班","classid":"2"}]};
    var b =  {"CODE":{"ERROR_CODE":0},"DATA":[{"xm":"张三","identityid":460},{"xm":"李四","identityid":462},{"xm":"王五","identityid":864},{"xm":"赵六","identityid":866}]};
    a.DATA[0]["classmate"]=b.DATA;
      

  3.   

    String a = "{'CODE':{'ERROR_CODE':0},'DATA':[{'bj':'初11级02班','classid':'2'}]}";
    String b =  "{'CODE':{'ERROR_CODE':0},'DATA':[{'xm':'张三','identityid':460},{'xm':'李四','identityid':462},{'xm':'王五','identityid':864},{'xm':'赵六','identityid':866}]}";

    JSONObject ja = JSONObject.fromObject(a); 
    JSONObject jb = JSONObject.fromObject(b); 

    ja.getJSONArray("DATA").getJSONObject(0).put("classmate",jb.get("DATA"));
    System.out.println(ja.toString());