读取一个file.txt文件中的9,6,8,3,4,1,2,5,0,7整数,并排序 出了点问题
FileInputStream fis = new FileInputStream(new File("E:\\file.txt"));
byte[] b = new byte[1024];
int len = fis.read(b);
String str = new String(b, 0, len);
String[] newstr = str.split(",");
for(int i=0;i<newstr.length;i++){
String temp = null;
for(int j=i+1;j<newstr.length;j++){
if(Integer.parseInt(newstr[i])>(Integer.parseInt(newstr[j]))){
temp = newstr[i];
newstr[i] = newstr[j];
newstr[j] = temp;
}
}
}Integer.parseInt(newstr[0])没法转成int,9前面好像还有个东西。
求指教啊
FileInputStream fis = new FileInputStream(new File("E:\\file.txt"));
byte[] b = new byte[1024];
int len = fis.read(b);
String str = new String(b, 0, len);
String[] newstr = str.split(",");
for(int i=0;i<newstr.length;i++){
String temp = null;
for(int j=i+1;j<newstr.length;j++){
if(Integer.parseInt(newstr[i])>(Integer.parseInt(newstr[j]))){
temp = newstr[i];
newstr[i] = newstr[j];
newstr[j] = temp;
}
}
}Integer.parseInt(newstr[0])没法转成int,9前面好像还有个东西。
求指教啊
file里的内容为这个改了下代码打印结果为上面多了个莫名其妙的东西实在搞不定
import java.io.FileInputStream;
import java.io.InputStream;public class InputStreamTest1
{
public static void main(String[] args) throws Exception
{
InputStream is = new FileInputStream("c:/file.txt");
byte[] buffer = new byte[200];
int length;
String temp = null;
while(-1 != (length = is.read(buffer, 0, 200)))
{
String str = new String(buffer,0, length); System.out.println(str);
}
is.close();
}
}