例如
string a = "1,2,3,4,5,6" public int[] StringtoInt(String str) {
int ret[] = new int[6];
StringTokenizer toKenizer = new StringTokenizer(str, ",");
String[] strx = new String[toKenizer.countTokens()];
for (int i = 0; i <= toKenizer.countTokens(); i++) {
strx[i] = toKenizer.nextToken();
ret[i] = Integer.valueOf(strx[i]);
}
return ret;
}在执行
for (int i : StringtoInt(a))的时候
i的值为1,2,3,0,0,0为什么会这样呢。。请问是哪儿出了问题
string a = "1,2,3,4,5,6" public int[] StringtoInt(String str) {
int ret[] = new int[6];
StringTokenizer toKenizer = new StringTokenizer(str, ",");
String[] strx = new String[toKenizer.countTokens()];
for (int i = 0; i <= toKenizer.countTokens(); i++) {
strx[i] = toKenizer.nextToken();
ret[i] = Integer.valueOf(strx[i]);
}
return ret;
}在执行
for (int i : StringtoInt(a))的时候
i的值为1,2,3,0,0,0为什么会这样呢。。请问是哪儿出了问题
System.out.println(Integer.valueOf(s));
};
嗯…… 得先转成int类型的数组再进行赋值呢 = =。
我那个转INT数组的写法请问哪儿有问题……
int ret[] = new int[6];
StringTokenizer toKenizer = new StringTokenizer(str, ",");
int i = 0;
while (toKenizer.hasMoreElements()) {
ret[i++] = Integer.valueOf(toKenizer.nextToken());
} return ret;
}
i <= toKenizer.countTokens(),把“toKenizer.countTokens()”改成“str.length”,即for (int i = 0; i <strx.length; i++)
不是很会用这个··· 是说toKenizer.countTokens()在后面会动态变化么。。能讲解下这个函数的意思么