这样的Exception该如何解决？

Question

  public static void main(String[] args) throws Exception {
    String[] urls = {
        "http://mil.news.sina.com.cn/2012-04-10/0428687123.html",
        "http://mil.news.sina.com.cn/2012-04-12/0731687387.html",
        "http://news.sina.com.cn/c/2012-04-13/044224264609.shtml"
    };
    final Pattern titlePattern = Pattern
        .compile("<h1 id=\"artibodyTitle\".*?>(.*?)</h1>");
    final Pattern wordCountPattern = Pattern.compile("\u515a|\u56fd\u5bb6");
    for (final String url : urls) {
      new Thread() {        public void run() {
          BufferedReader reader = null;
          try {
            reader = new BufferedReader(new InputStreamReader(
                new URL(url).openStream(), "GB2312"));
            String line;
            String title = null;
            int[] count = new int[2];
            while ((line = reader.readLine()) != null) {
              if (title == null) {
                Matcher titleMatcher = titlePattern.matcher(line);
                if (titleMatcher.find()) {
                  title = titleMatcher.group(1);
                }
              }
              Matcher wordCountMatcher = wordCountPattern.matcher(line);
              while (wordCountMatcher.find()) {
                String word = wordCountMatcher.group();
                count[word.length() >> 1]++;
              }
            }
            if (count[0] > count[1]) {
              throw new RuntimeException(
                  String.format("%s[%s] \u515a:%d > \u56fd\u5bb6:%d",
                                title,
                                url,
                                count[0],
                                count[1]));
            }
            System.out.printf("%s[%s] is good!", title, url);
          } catch (IOException ex) {
            ex.printStackTrace();
          } finally {
            if (reader != null) {
              try {
                reader.close();
                reader = null;
              } catch (Exception ex) {
              }
            }
          }
        }
      }.start();
    }
  }

Answer 1

3个线程一律count[0]远远大于count[1]

Answer 2

solution：add following line before Matcher wordCountMatcher = wordCountPattern.matcher(line);
 line=line.replaceAll("\u515a","\u4EBA\u6C11");

Answer 3

楼主你是哪个单位的？！你是为\u515a说话的，还是为\u56fd\u5bb6说话的？！

Answer 4

貌似有句说明了这点没有\u515a就没有新中国.............
所以\u515a 铁定大于 \u56fd\u5bb6

Answer 5

看看u515a铸就的新中国的冰山一角：
\u559D\u6C34\u6B7B
\u8EB2\u732B\u732B
\u674E\u521A
\u6BD2\u5976\u7C89
\u6740\u7AE5
\u9ED1\u76D1\u72F1

Answer 6

\u515a=党
\u56fd=人
\u5bb6=民

Answer 7

统计这些东西有意义么，一篇文章中有1w个\u515a，但是结尾有于句话，说所有这些都是为了\u56fd\u5bb6。