Fizzbuzz问题求助

Question

我是新手这段代码编译不通过啊，求帮助。
import  java.util.Scanner;
public class Fizzbuzz
{
     public static void main(String[] args) 
           {   int a=1;
            while(a==1){      
                 Scanner scanner = new Scanner(System.in);
                 System.out.print("请输入整数:");        
                int i;i = scanner.next();       
                 try{
                       i=Integer.parseInt(i);
                 }catch(Exception e){
                  System.out.println("输入有错，请重新输入：");
                  }
 
                 if(i%15==0) 
                     System.out.print ("FizzBuzz");
                 else if(i%3==0)
                     System.out.print ("Fizz");
                 else if(i%5==0)                 
                     System.out.print ("Buzz");
                 else 
                     System.out.print (i);                              System.out.print("是否继续:1（是）0（否）"); 
                  
                 a = scanner.nextInt();
               }     }
}

Answer 1

import java.util.Scanner;
public class Fizzbuzz
{
  public static void main(String[] args) 
  { int a=1;
  while(a==1){  
  Scanner scanner = new Scanner(System.in);
  System.out.print("请输入整数:");  
  int i =0 ;  
  try{
  i=Integer.parseInt(scanner.next());
  }catch(Exception e){
  System.out.println("输入有错，请重新输入：");
  }
 
  if(i%15==0) 
  System.out.print ("FizzBuzz");
  else if(i%3==0)
  System.out.print ("Fizz");
  else if(i%5==0)  
  System.out.print ("Buzz");
  else 
  System.out.print (i);    System.out.print("是否继续:1（是）0（否）"); 
   
  a = scanner.nextInt();
}  }
}i = scanner.next(); 
这句话不对，scanner.next()返回值是String类型，不能赋值给i