从键盘输入一个整数(1~20)
则以该数字为矩阵的大小,把1,2,3…n*n 的数字按照顺时针螺旋的形式填入其中。例如:
输入数字2,则程序输出:
1 2
4 3
输入数字3,则程序输出:
1 2 3
8 9 4
7 6 5
输入数字4, 则程序输出:
1 2 3 4
12 13 14 5
11 16 15 6
10 9 8 7
这个程序怎么写呀?请各位帮忙写一下!
则以该数字为矩阵的大小,把1,2,3…n*n 的数字按照顺时针螺旋的形式填入其中。例如:
输入数字2,则程序输出:
1 2
4 3
输入数字3,则程序输出:
1 2 3
8 9 4
7 6 5
输入数字4, 则程序输出:
1 2 3 4
12 13 14 5
11 16 15 6
10 9 8 7
这个程序怎么写呀?请各位帮忙写一下!
http://topic.csdn.net/u/20110428/12/e6942638-849e-4bcc-a576-a2fa818c09f0.html
import java.io.IOException;
import java.io.InputStreamReader;public class BBB {
public static int d;
public static void main(String[] args) {
BBB l=new BBB();
System.out.println("请输入一个数:");
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
try {
String str = br.readLine();
d= Integer.parseInt(str);} catch (NumberFormatException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
int [][]a=new int [d][d];
System.out.println("排列:");
int n=0;
boolean flay=true;
while(flay&&n<d)
{
for(int i=n;i<d-n;i++)
if(n==0)
a[n][i]=i+1;
else
a[n][i]=a[n][i-1]+1;
flay=l.Chu(a);
if(flay==false) break;
for(int i=n;i<d-n-1;i++)
if(n==0)
a[i+1][d-1-n]=i+d+1;
else
a[i+1][d-1-n]=a[i][d-1-n]+1;
for(int i=n;i<d-n-1;i++)
if(n==0)
a[d-1-n][i]=a[d-1-n][d-1-n]+d-1-i;
else
a[d-1-n][i]=a[d-1-n][d-1-n]+d-1-n-i;
flay=l.Chu(a);
if(flay==false) break;
for(int i=1+n;i<d-n-1;i++)
if(n==0)
a[i][n]=a[d-1-n][n]+d-1-i;
else
a[i][n]=a[d-1-n][n]+d-1-i-n;
flay=l.Chu(a);
n++;
}
l.OUT(a);
}
public void OUT(int [] []a)
{
for(int i=0;i<d;i++)
{
for(int j=0;j<d;j++)
{
System.out.print(a[i][j]+"\t");
}
System.out.println();
}
}
public boolean Chu(int [] []a)
{for(int i=0;i<d;i++)
{
for(int j=0;j<d;j++)
{
if(a[i][j]==0)
return true;
}
}
return false;
}
}
public static void main(String[] args) {
int num=1;
int cirCle[][]=new int[20][20];
int inputNum;
int i,j,line,t;
Scanner in=new Scanner(System.in);
inputNum=in.nextInt();
line=inputNum;
for(t=0;t<line;t++){
for(i=t,j=t;j<inputNum-t;j++){ //赋值上外围
cirCle[i][j]=num;
num++;
}
for(j=j-1,i=i+1;i<inputNum-t;i++){ //赋值右外围
cirCle[i][j]=num;
num++;
}
for(j=j-1,i=i-1;j>=t;j--){ //赋值下外围
cirCle[i][j]=num;
num++;
}
for(j=j+1,i=i-1;i>t;i--){ //赋值左外围
cirCle[i][j]=num;
num++;
}
}
for(int m=0;m<line;m++){ //输出结果
for(int n=0;n<line;n++){
System.out.print(cirCle[m][n]+" ");
}
System.out.println();
}
}
}
import java.util.*;public class Test
{
private final static int UP = 0;
private final static int DOWN = 1;
private final static int LEFT = 2;
private final static int RIGHT = 3;
public static int getLength(int num)
{
int i;
for (i = 1; num != 0; i++)
num /= 10;
return i;
}
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
int size = in.nextInt();
int data[][] = new int[size][size];
int toward = Test.RIGHT;
for (int num = 1, i = 0, j = 0; num <= size * size; num++)
{
data[i][j] = num;
switch (toward)
{
case UP:
if (i == 0 || data[i - 1][j] != 0)
{
toward = RIGHT;
j++;
}
else
i--;
break;
case DOWN:
if (i == size - 1 || data[i + 1][j] != 0)
{
toward = LEFT;
j--;
}
else
i++;
break;
case LEFT:
if (j == 0 || data[i][j - 1] != 0)
{
toward = UP;
i--;
}
else
j--;
break;
case RIGHT:
if (j == size - 1 || data[i][j + 1] != 0)
{
toward = DOWN;
i++;
}
else
j++;
break;
}
}
int l = getLength(size * size);
for (int i = 0; i < size; i++)
{
for (int j = 0; j < size; j++)
{
System.out.printf("%-" + l + "d", data[i][j]);
}
System.out.println();
}
}
}
public static void main(String[] args) {
final int count = 10;
final int max = count * count;
int[][] data = new int[count][count];
int x = -1, y = 0, cur = 0;
while (cur < max) {
for (; x + 1 < count && data[x + 1][y] == 0; data[y][++x] = ++cur);
for (; y + 1 < count && data[x][y + 1] == 0; data[++y][x] = ++cur);
for (; x - 1 >= 0 && data[y][x - 1] == 0; data[y][--x] = ++cur);
for (; y - 1 >= 0 && data[y - 1][x] == 0; data[--y][x] = ++cur);
} for (int i = 0; i < count; ++i) {
for (int j = 0; j < data[i].length; ++j) {
System.out.printf("%-3d ", data[i][j]);
}
System.out.println();
}
}
}
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.println("请输入一个正整数:");
int n=sc.nextInt(); //从 System.in 中读取一个数
int i=1,j=0,k=0,flag=0,sign=0;
int[][] arry=new int[n][n]; for(i=1;i<=n*n;){
for(k=0+flag;k<n-flag;k++){
arry[j+sign][k]=i++;
}
for(j=1+flag;j<n-flag;j++){
arry[j][k-1]=i++;
}
for(k=k-2;k>=0+flag;k--){
arry[j-1][k]=i++;
}
for(j=j-2;j>=1+flag;j--){
arry[j][k+1]=i++;
}
flag++;
sign=1;
}
for(i=0;i<n;i++){
for(j=0;j<n;j++)
System.out.print(arry[i][j]+" ");
System.out.println();
}
}
}一样国信蓝点杯。一起加油啊。