IO包里解压ZIP格式文件

Question

 看了API中关于ZIPINPUTSTREAM的例子,照着输入后,运行出错,
import  java.util.zip.*;
import  java.io.*;
   public  class ZipTest{
   private  static final int BUFFER=2048;
   
   public static void main(String [] args){
   
   try{
 
      ZipInputStream zis=new ZipInputStream(new DataInputStream(new FileInputStream("D:/JAVa/Zip/testZip.zip")));
 
      ZipEntry  entry;      String  path="D:/JAVa/Zip/";[ 18,]     while( (entry=zis.getNextEntry())!=null){
            System.out.println("ENTRY"+entry);
            int  count;
            byte  [] data=new  byte[BUFFER];
         
            FileOutputStream fos=new FileOutputStream(path+entry.getName());
         
            ZipOutputStream  dest=null;
            dest=new ZipOutputStream(new BufferedOutputStream(fos,BUFFER));
          while( (count=zis.read(data,0,BUFFER))!=-1){
                   
                 dest.write(data,0,count);
             }
              dest.flush();
              dest.close();
           }
           zis.close();
          }catch(IOException e){
                 e.printStackTrace();}
            }
}
Exception in thread "main" java.lang.IllegalArgumentException
at java.util.zip.ZipInputStream.getUTF8String(ZipInputStream.java:293)
at java.util.zip.ZipInputStream.readLOC(ZipInputStream.java:247)
at java.util.zip.ZipInputStream.getNextEntry(ZipInputStream.java:74)
at zip.ZipTest.main(ZipTest.java:18)
18行是   while( (entry=zis.getNextEntry())!=null){非法参数异常,想不通额,难道是路径有错吗 N  希望有人指点下
 

Answer 1

public static void main(String[] args) throws Exception {
String zipname = "C:/b.zip";
ZipFile zipFile = new ZipFile(zipname);
Enumeration enumeration = zipFile.entries();
while (enumeration.hasMoreElements()) {
ZipEntry zipEntry = (ZipEntry) enumeration.nextElement();
System.out.println("Unzipping: " + zipEntry.getName());
BufferedInputStream bis = new BufferedInputStream(zipFile
.getInputStream(zipEntry));
int size;
byte[] buffer = new byte[2048];
BufferedOutputStream bos = new BufferedOutputStream(
new FileOutputStream(zipEntry.getName()), buffer.length);
while ((size = bis.read(buffer, 0, buffer.length)) != -1) {
bos.write(buffer, 0, size);
}
bos.flush();
bos.close();
bis.close();
}
}

Answer 2

刚做完，给你了。呵呵
    /**
     * 解压 zip 文件
     * 
     * @param zipFile
     *            待解压的 zip 文件
     * 
     * @param path
     *            解压的目的地
     * 
     * @throws IOException
     */
    private static void unZip(File zipFile, String path) throws IOException {
        ZipInputStream zin = new ZipInputStream(new FileInputStream(zipFile));
        ZipEntry entry = null;        // 创建解压目录
        File unzipDirectory = new File(path);
        unzipDirectory.mkdir();        while ((entry = zin.getNextEntry()) != null) {
            if (entry.isDirectory()) {
                // 如果是目录，则创建目录
                File dataDirectory = new File(path, entry.getName());
                dataDirectory.mkdir();
                zin.closeEntry();
            } else {
                // 如果是文件，则创建文件
                FileOutputStream fout = new FileOutputStream(path + "\\"
                        + entry.getName());
                DataOutputStream dout = new DataOutputStream(fout);
                byte[] b = new byte[1024];
                int len = 0;
                while ((len = zin.read(b)) != -1) {
                    dout.write(b, 0, len);
                }
                dout.close();
                fout.close();
                zin.closeEntry();
            }
        }        if (zin != null) {
            zin.close();
        }
    }

Answer 3

你的zip中文件名是中文的吧？