目的:把字符串中以f开头的一串数字保留,其他数字替换为*
public static void main(String[] args) {
String s ="abc11,cd123 f7895";
String s2 = s.replaceAll("(?<!f)[0-9]+?", "*");
System.out.println(s);
System.out.println(s2);
}结果是
abc11,cd123 f1123
abc**,cd*** f7***
怎样让他保留f7895而不是f7?
public static void main(String[] args) {
String s ="abc11,cd123 f7895";
String s2 = s.replaceAll("(?<!f)[0-9]+?", "*");
System.out.println(s);
System.out.println(s2);
}结果是
abc11,cd123 f1123
abc**,cd*** f7***
怎样让他保留f7895而不是f7?
String s2 = s.replaceAll("(?<!e)[0-9]+?", "*");
String[] s2 = s.split("(?<!\\w)");
StringBuffer sb = new StringBuffer();
for(int i = 1; i < s2.length;i++) {
if(s2[i].charAt(0)!='f') {
sb.append(s2[i].replaceAll("\\d","*"));
}
else {
sb.append(s2[i]);
}
}
System.out.println(s);
System.out.println(sb);
Pattern p = Pattern.compile(".*?\\d+");
Matcher m = p.matcher(s);
StringBuffer sb = new StringBuffer();
while (m.find()) {
if (!m.group().matches("\\W*f\\d+")) { // 如果是f后跟数字不替换就用 .*?f\\d+
m.appendReplacement(sb, m.group().replaceAll("\\d+", ""));
}
}
m.appendTail(sb);
System.out.println(sb);
str=" "+str+" ";
Pattern pat=Pattern.compile("[^f0-9][0-9]+(?=[^0-9])");
Matcher mcr=pat.matcher(str);
StringBuffer sb=new StringBuffer();
while(mcr.find()){
mcr.appendReplacement(sb, mcr.group().replaceAll("[0-9]", "*"));
}
mcr.appendTail(sb);
str=sb.toString().replaceAll("^ | $","");
System.out.println(str);
如果不区分数字多少的话 就简单了
String str="abc11,cd123 f7895";
str=" "+str+" ";
str=str.replaceAll("([^f0-9])[0-9]+(?=[^0-9])", "$1*");
str=str.replaceAll("^ | $","");
System.out.println(str);
String s = "abc11,cd123 f7895 abcd1234 ef1234 abc123";
s = s.replaceAll("([^f\\d]+)\\d+", "$1");
System.out.println(s);