请教如何用正则表达式表示这个字符串

Question

我有一个字符串，内容为：
\n<a href=\"http:\/\/aaaaaaaaaa.bbbb.ccccccc\/ad?\/asdfasdf\/asdfasdfsd*1asdfasdas!\/a\/asdfasdfasd\"><img src=\"http:\/\/asdfasdf.asdfasdf.as.com\/psb?\/asdfasdfasdf!\/a\/asdfasdf\" alt=\"\"\/><\/a>\nmy 123\n12345678我要使用正则表达式表示<a href ....</a>这段内容，然后用str = str1.replaceAll(reg,"");来去掉这段正则表达式所表示的内容，最后剩下的字符串为：
\nmy 123\n12345678请高手指教如何写这段正则表达式呢？小妹多谢啦。

Answer 1

<script>
var a = "\n<a href=\"http:\/\/aaaaaaaaaa.bbbb.ccccccc\/ad?\/asdfasdf\/asdfasdfsd*1asdfasdas!\/a\/asdfasdfasd\"><img src=\"http:\/\/asdfasdf.asdfasdf.as.com\/psb?\/asdfasdfasdf!\/a\/asdfasdf\" alt=\"\"\/><\/a>\nmy 123\n12345678";
a = a.replace(/<a.*?><\/a>/,"");
alert(a);
</script>

Answer 2

正则可以这么写
String reg = "<a href=\\S*/a>";
str = str.replaceAll(reg, "");

Answer 3

我这样写的：
String reg = "<a href=\\S*</a>" ;
String str = "\n<a href=\"http://abcd/psb?/abceasd/asdfas*asdfasdf!/a/asdfsdfasdf\"><img src=\"http://asdfasdf.asdf.asdf/psb?/asdfasdf/asdfasdfew232*asdfasdf*fBum4!/a/asdfasdf\" alt=\"\"/></a>\nasdfasdfasdf\nasdfas asdfas asdf" ;
String str1 = str.replaceAll(reg, "");
System.out.println("-----------str="+str);
System.out.println("---------str1="+str1);但打印结果为：
-----------str=
<a href="http://abcd/psb?/abceasd/asdfas*asdfasdf!/a/asdfsdfasdf"><img src="http://asdfasdf.asdf.asdf/psb?/asdfasdf/asdfasdfew232*asdfasdf*fBum4!/a/asdfasdf" alt=""/></a>
asdfasdfasdf
asdfas asdfas asdf
---------str1=
<a href="http://abcd/psb?/abceasd/asdfas*asdfasdf!/a/asdfsdfasdf"><img src="http://asdfasdf.asdf.asdf/psb?/asdfasdf/asdfasdfew232*asdfasdf*fBum4!/a/asdfasdf" alt=""/></a>
asdfasdfasdf
asdfas asdfas asdf仍然没有过滤掉<a href=...</a>之间的部分，怎么回事呢？

Answer 4

你的字符串中有空白字符……
 
把正则换成：String reg = "<a href=\\p{ASCII}*</a>";

Answer 5

kiss601459202，真的太感谢啦！能帮我解释下你写的正则表达式的意思吗？

Answer 6

了解了，是所有的ACSII字符，多谢啦。给分！