求一个JAVA加密的一个算法(用md5或者其它算法) 40分 看你的了 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 常用的不就几种么MD5,SHA,RSAhttp://www.cnblogs.com/mycodelife/archive/2009/04/22/1441624.html public class MD5_SRC{ public static void main(String args[]){ System.out.println (MD5.toMD5("a")); }} class MD5{ static final int S11 = 7; static final int S12 = 12; static final int S13 = 17; static final int S14 = 22; static final int S21 = 5; static final int S22 = 9; static final int S23 = 14; static final int S24 = 20; static final int S31 = 4; static final int S32 = 11; static final int S33 = 16; static final int S34 = 23; static final int S41 = 6; static final int S42 = 10; static final int S43 = 15; static final int S44 = 21; static final char Hex[]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'}; static final byte PADDING[] = { -128, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; private long state[]; private long count[]; private byte buffer[]; public String digestHexStr; private byte digest[]; private byte test; public String getMD5ofStr(String s) {//返回MD5串; int i; md5Init(); md5Update(s.getBytes(), s.length()); md5Final(); digestHexStr = ""; for(i = 0;i<16;i++) digestHexStr=digestHexStr+byteHEX(digest[i]); return digestHexStr; } public MD5() { state = new long[4]; count = new long[2]; buffer = new byte[64]; digest = new byte[16]; md5Init(); } private void md5Init() {//初始化部分变量; count[0] = 0L; count[1] = 0L; state[0] = 0x67452301L; state[1] = 0xefcdab89L; state[2] = 0x98badcfeL; state[3] = 0x10325476L; } private long F(long l, long l1, long l2) { return l & l1 | ~l & l2; } private long G(long l, long l1, long l2) { return l & l2 | l1 & ~l2; } private long H(long l, long l1, long l2) { return l ^ l1 ^ l2; } private long I(long l, long l1, long l2) { return l1 ^ (l | ~l2); } private long FF(long l, long l1, long l2, long l3, long l4, long l5, long l6) { l += F(l1, l2, l3) + l4 + l6; l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5); l += l1; return l; } private long GG(long l, long l1, long l2, long l3, long l4, long l5, long l6) { l += G(l1, l2, l3) + l4 + l6; l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5); l += l1; return l; } private long HH(long l, long l1, long l2, long l3, long l4, long l5, long l6) { l += H(l1, l2, l3) + l4 + l6; l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5); l += l1; return l; } private long II(long l, long l1, long l2, long l3, long l4, long l5, long l6) { l += I(l1, l2, l3) + l4 + l6; l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5); l += l1; return l; } private void md5Update(byte abyte0[], int i) {//补位操作,abyte0为需要进行MD5加密的字符串,i为字符串长度; byte abyte1[] = new byte[64]; int k = (int)(count[0] >>> 3) & 0x3f; if((count[0] += i << 3) < (long)(i << 3)) count[1]++; count[1] += i >>> 29; int l = 64 - k; int j; if(i >= l) { md5Memcpy(buffer, abyte0, k, 0, l); md5Transform(buffer); for(j = l; j + 63 < i; j += 64) { md5Memcpy(abyte1, abyte0, 0, j, 64); md5Transform(abyte1); } k = 0; } else { j = 0; } md5Memcpy(buffer, abyte0, k, j, i - j); } private void md5Final() {//最终处理,将得到的128位(16字节)MD5码存放在digest数组中 byte abyte0[] = new byte[8]; Encode(abyte0, count, 8); int i = (int)(count[0] >>> 3) & 0x3f; int j = i >= 56 ? 120 - i : 56 - i; md5Update(PADDING, j); md5Update(abyte0, 8); Encode(digest, state, 16); } private void md5Memcpy(byte abyte0[], byte abyte1[], int i, int j, int k) { for(int l = 0; l < k; l++) abyte0[i + l] = abyte1[j + l]; } private void md5Transform(byte abyte0[]) { long l = state[0]; long l1 = state[1]; long l2 = state[2]; long l3 = state[3]; long al[] = new long[16]; Decode(al, abyte0, 64); l = FF(l, l1, l2, l3, al[0], 7L, 0xd76aa478L); l3 = FF(l3, l, l1, l2, al[1], 12L, 0xe8c7b756L); l2 = FF(l2, l3, l, l1, al[2], 17L, 0x242070dbL); l1 = FF(l1, l2, l3, l, al[3], 22L, 0xc1bdceeeL); l = FF(l, l1, l2, l3, al[4], 7L, 0xf57c0fafL); l3 = FF(l3, l, l1, l2, al[5], 12L, 0x4787c62aL); l2 = FF(l2, l3, l, l1, al[6], 17L, 0xa8304613L); l1 = FF(l1, l2, l3, l, al[7], 22L, 0xfd469501L); l = FF(l, l1, l2, l3, al[8], 7L, 0x698098d8L); l3 = FF(l3, l, l1, l2, al[9], 12L, 0x8b44f7afL); l2 = FF(l2, l3, l, l1, al[10], 17L, 0xffff5bb1L); l1 = FF(l1, l2, l3, l, al[11], 22L, 0x895cd7beL); l = FF(l, l1, l2, l3, al[12], 7L, 0x6b901122L); l3 = FF(l3, l, l1, l2, al[13], 12L, 0xfd987193L); l2 = FF(l2, l3, l, l1, al[14], 17L, 0xa679438eL); l1 = FF(l1, l2, l3, l, al[15], 22L, 0x49b40821L); l = GG(l, l1, l2, l3, al[1], 5L, 0xf61e2562L); l3 = GG(l3, l, l1, l2, al[6], 9L, 0xc040b340L); l2 = GG(l2, l3, l, l1, al[11], 14L, 0x265e5a51L); l1 = GG(l1, l2, l3, l, al[0], 20L, 0xe9b6c7aaL); l = GG(l, l1, l2, l3, al[5], 5L, 0xd62f105dL); l3 = GG(l3, l, l1, l2, al[10], 9L, 0x2441453L); l2 = GG(l2, l3, l, l1, al[15], 14L, 0xd8a1e681L); l1 = GG(l1, l2, l3, l, al[4], 20L, 0xe7d3fbc8L); l = GG(l, l1, l2, l3, al[9], 5L, 0x21e1cde6L); l3 = GG(l3, l, l1, l2, al[14], 9L, 0xc33707d6L); l2 = GG(l2, l3, l, l1, al[3], 14L, 0xf4d50d87L); l1 = GG(l1, l2, l3, l, al[8], 20L, 0x455a14edL); l = GG(l, l1, l2, l3, al[13], 5L, 0xa9e3e905L); l3 = GG(l3, l, l1, l2, al[2], 9L, 0xfcefa3f8L); l2 = GG(l2, l3, l, l1, al[7], 14L, 0x676f02d9L); l1 = GG(l1, l2, l3, l, al[12], 20L, 0x8d2a4c8aL); l = HH(l, l1, l2, l3, al[5], 4L, 0xfffa3942L); l3 = HH(l3, l, l1, l2, al[8], 11L, 0x8771f681L); l2 = HH(l2, l3, l, l1, al[11], 16L, 0x6d9d6122L); l1 = HH(l1, l2, l3, l, al[14], 23L, 0xfde5380cL); l = HH(l, l1, l2, l3, al[1], 4L, 0xa4beea44L); l3 = HH(l3, l, l1, l2, al[4], 11L, 0x4bdecfa9L); l2 = HH(l2, l3, l, l1, al[7], 16L, 0xf6bb4b60L); l1 = HH(l1, l2, l3, l, al[10], 23L, 0xbebfbc70L); l = HH(l, l1, l2, l3, al[13], 4L, 0x289b7ec6L); l3 = HH(l3, l, l1, l2, al[0], 11L, 0xeaa127faL); l2 = HH(l2, l3, l, l1, al[3], 16L, 0xd4ef3085L); l1 = HH(l1, l2, l3, l, al[6], 23L, 0x4881d05L); l = HH(l, l1, l2, l3, al[9], 4L, 0xd9d4d039L); l3 = HH(l3, l, l1, l2, al[12], 11L, 0xe6db99e5L); l2 = HH(l2, l3, l, l1, al[15], 16L, 0x1fa27cf8L); l1 = HH(l1, l2, l3, l, al[2], 23L, 0xc4ac5665L); l = II(l, l1, l2, l3, al[0], 6L, 0xf4292244L); l3 = II(l3, l, l1, l2, al[7], 10L, 0x432aff97L); l2 = II(l2, l3, l, l1, al[14], 15L, 0xab9423a7L); l1 = II(l1, l2, l3, l, al[5], 21L, 0xfc93a039L); l = II(l, l1, l2, l3, al[12], 6L, 0x655b59c3L); l3 = II(l3, l, l1, l2, al[3], 10L, 0x8f0ccc92L); l2 = II(l2, l3, l, l1, al[10], 15L, 0xffeff47dL); l1 = II(l1, l2, l3, l, al[1], 21L, 0x85845dd1L); l = II(l, l1, l2, l3, al[8], 6L, 0x6fa87e4fL); l3 = II(l3, l, l1, l2, al[15], 10L, 0xfe2ce6e0L); l2 = II(l2, l3, l, l1, al[6], 15L, 0xa3014314L); l1 = II(l1, l2, l3, l, al[13], 21L, 0x4e0811a1L); l = II(l, l1, l2, l3, al[4], 6L, 0xf7537e82L); l3 = II(l3, l, l1, l2, al[11], 10L, 0xbd3af235L); l2 = II(l2, l3, l, l1, al[2], 15L, 0x2ad7d2bbL); l1 = II(l1, l2, l3, l, al[9], 21L, 0xeb86d391L); state[0] += l; state[1] += l1; state[2] += l2; state[3] += l3; } private void Encode(byte abyte0[], long al[], int i) {//转换函数,将al中long型的变量输出到byte型的数组abyte0中, //低位字节在前,高位字节在后; int j = 0; for(int k = 0; k < i; k += 4) { abyte0[k] = (byte)(int)(al[j] & 255L); abyte0[k + 1] = (byte)(int)(al[j] >>> 8 & 255L); abyte0[k + 2] = (byte)(int)(al[j] >>> 16 & 255L); abyte0[k + 3] = (byte)(int)(al[j] >>> 24 & 255L); j++; } } private void Decode(long al[], byte abyte0[], int i) { int j = 0; for(int k = 0; k < i; k += 4) { al[j] = b2iu(abyte0[k]) | b2iu(abyte0[k + 1]) << 8 | b2iu(abyte0[k + 2]) << 16 | b2iu(abyte0[k + 3]) << 24; j++; } } public static long b2iu(byte byte0) { return byte0 >= 0 ? byte0 : byte0 & 0xff; } public static String byteHEX(byte byte0) {//字节到十六进制的ASCII码转换 char ac[] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' }; char ac1[] = new char[2]; ac1[0] = ac[byte0 >>> 4 & 0xf]; ac1[1] = ac[byte0 & 0xf]; String s = new String(ac1); return s; } public static String toMD5(String s) { MD5 md5 = new MD5(); return md5.getMD5ofStr(s); }} 楼主可以尝试使用多个加密算法多次加密嘿嘿MD5+一次,RSA再加一次。 public class EncryptPassword { private final static String[] hexDigits = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "a", "b", "c", "d", "e", "f"}; /** * 转换字节数组为16进制字串 * @param b 字节数组 * @return 16进制字串 */ public static String byteArrayToHexString(byte[] b) { StringBuffer resultSb = new StringBuffer(); for (int i = 0; i < b.length; i++) { resultSb.append(byteToHexString(b[i])); } return resultSb.toString(); } private static String byteToHexString(byte b) { int n = b; if (n < 0) n = 256 + n; int d1 = n / 16; int d2 = n % 16; return hexDigits[d1] + hexDigits[d2]; } public static String MD5Encode(String origin) { String resultString = null; try { resultString=new String(origin); MessageDigest md = MessageDigest.getInstance("MD5"); resultString=byteArrayToHexString(md.digest(resultString.getBytes())); } catch (Exception ex) { } return resultString; } public static void main(String[] args){ System.err.println(MD5Encode("")); System.err.println(MD5Encode("a")); System.err.println(MD5Encode("abc")); System.err.println(MD5Encode("message digest")); System.err.println(MD5Encode("abcdefghijklmnopqrstuvwxyz")); } //MD5 ("") = d41d8cd98f00b204e9800998ecf8427e //MD5 ("a") = 0cc175b9c0f1b6a831c399e269772661 //MD5 ("abc") = 900150983cd24fb0d6963f7d28e17f72 //MD5 ("message digest") = f96b697d7cb7938d525a2f31aaf161d0 //MD5 ("abcdefghijklmnopqrstuvwxyz") = c3fcd3d76192e4007dfb496cca67e13b}楼主使用时要记住,MD5是不可逆的,并且有很小的几率产生碰撞。优点是算法速度快,资源耗费小,主要用于文件校验和密码验证,SHA-1也不错! 空指针异常,看了好久好久,实在看不出来,求帮助 大家看看这段代码错在哪里? 对于初学者,JSP那本书比较好? IBM JDK1.4.2 javacore分析原因 分享:java经典题目 执行时的问题,请高手指点! 请教各位大神!!! 汉子返回(JTextPane)?大小,颜色设置?在线解决给分。 一个关于计时器的问题!! 关于Java的返回值问题:太奇怪了!!! ftp4j上传大文件的问题 <script>alert('ffff')</script>
http://www.cnblogs.com/mycodelife/archive/2009/04/22/1441624.html
System.out.println (MD5.toMD5("a"));
}} class MD5
{
static final int S11 = 7;
static final int S12 = 12;
static final int S13 = 17;
static final int S14 = 22;
static final int S21 = 5;
static final int S22 = 9;
static final int S23 = 14;
static final int S24 = 20;
static final int S31 = 4;
static final int S32 = 11;
static final int S33 = 16;
static final int S34 = 23;
static final int S41 = 6;
static final int S42 = 10;
static final int S43 = 15;
static final int S44 = 21;
static final char Hex[]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
static final byte PADDING[] = {
-128, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0
};
private long state[];
private long count[];
private byte buffer[];
public String digestHexStr;
private byte digest[];
private byte test;
public String getMD5ofStr(String s)
{//返回MD5串;
int i;
md5Init();
md5Update(s.getBytes(), s.length());
md5Final();
digestHexStr = "";
for(i = 0;i<16;i++)
digestHexStr=digestHexStr+byteHEX(digest[i]);
return digestHexStr;
}
public MD5()
{
state = new long[4];
count = new long[2];
buffer = new byte[64];
digest = new byte[16];
md5Init();
}
private void md5Init()
{//初始化部分变量;
count[0] = 0L;
count[1] = 0L;
state[0] = 0x67452301L;
state[1] = 0xefcdab89L;
state[2] = 0x98badcfeL;
state[3] = 0x10325476L;
}
private long F(long l, long l1, long l2)
{
return l & l1 | ~l & l2;
}
private long G(long l, long l1, long l2)
{
return l & l2 | l1 & ~l2;
}
private long H(long l, long l1, long l2)
{
return l ^ l1 ^ l2;
}
private long I(long l, long l1, long l2)
{
return l1 ^ (l | ~l2);
}
private long FF(long l, long l1, long l2, long l3, long l4, long l5, long l6)
{
l += F(l1, l2, l3) + l4 + l6;
l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5);
l += l1;
return l;
}
private long GG(long l, long l1, long l2, long l3, long l4, long l5, long l6)
{
l += G(l1, l2, l3) + l4 + l6;
l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5);
l += l1;
return l;
}
private long HH(long l, long l1, long l2, long l3, long l4, long l5, long l6)
{
l += H(l1, l2, l3) + l4 + l6;
l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5);
l += l1;
return l;
}
private long II(long l, long l1, long l2, long l3, long l4, long l5, long l6)
{
l += I(l1, l2, l3) + l4 + l6;
l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5);
l += l1;
return l;
}
private void md5Update(byte abyte0[], int i)
{//补位操作,abyte0为需要进行MD5加密的字符串,i为字符串长度;
byte abyte1[] = new byte[64];
int k = (int)(count[0] >>> 3) & 0x3f;
if((count[0] += i << 3) < (long)(i << 3))
count[1]++;
count[1] += i >>> 29;
int l = 64 - k;
int j;
if(i >= l)
{
md5Memcpy(buffer, abyte0, k, 0, l);
md5Transform(buffer);
for(j = l; j + 63 < i; j += 64)
{
md5Memcpy(abyte1, abyte0, 0, j, 64);
md5Transform(abyte1);
}
k = 0;
} else
{
j = 0;
}
md5Memcpy(buffer, abyte0, k, j, i - j);
}
private void md5Final()
{//最终处理,将得到的128位(16字节)MD5码存放在digest数组中
byte abyte0[] = new byte[8];
Encode(abyte0, count, 8);
int i = (int)(count[0] >>> 3) & 0x3f;
int j = i >= 56 ? 120 - i : 56 - i;
md5Update(PADDING, j);
md5Update(abyte0, 8);
Encode(digest, state, 16);
}
private void md5Memcpy(byte abyte0[], byte abyte1[], int i, int j, int k)
{
for(int l = 0; l < k; l++)
abyte0[i + l] = abyte1[j + l];
}
private void md5Transform(byte abyte0[])
{
long l = state[0];
long l1 = state[1];
long l2 = state[2];
long l3 = state[3];
long al[] = new long[16];
Decode(al, abyte0, 64);
l = FF(l, l1, l2, l3, al[0], 7L, 0xd76aa478L);
l3 = FF(l3, l, l1, l2, al[1], 12L, 0xe8c7b756L);
l2 = FF(l2, l3, l, l1, al[2], 17L, 0x242070dbL);
l1 = FF(l1, l2, l3, l, al[3], 22L, 0xc1bdceeeL);
l = FF(l, l1, l2, l3, al[4], 7L, 0xf57c0fafL);
l3 = FF(l3, l, l1, l2, al[5], 12L, 0x4787c62aL);
l2 = FF(l2, l3, l, l1, al[6], 17L, 0xa8304613L);
l1 = FF(l1, l2, l3, l, al[7], 22L, 0xfd469501L);
l = FF(l, l1, l2, l3, al[8], 7L, 0x698098d8L);
l3 = FF(l3, l, l1, l2, al[9], 12L, 0x8b44f7afL);
l2 = FF(l2, l3, l, l1, al[10], 17L, 0xffff5bb1L);
l1 = FF(l1, l2, l3, l, al[11], 22L, 0x895cd7beL);
l = FF(l, l1, l2, l3, al[12], 7L, 0x6b901122L);
l3 = FF(l3, l, l1, l2, al[13], 12L, 0xfd987193L);
l2 = FF(l2, l3, l, l1, al[14], 17L, 0xa679438eL);
l1 = FF(l1, l2, l3, l, al[15], 22L, 0x49b40821L);
l = GG(l, l1, l2, l3, al[1], 5L, 0xf61e2562L);
l3 = GG(l3, l, l1, l2, al[6], 9L, 0xc040b340L);
l2 = GG(l2, l3, l, l1, al[11], 14L, 0x265e5a51L);
l1 = GG(l1, l2, l3, l, al[0], 20L, 0xe9b6c7aaL);
l = GG(l, l1, l2, l3, al[5], 5L, 0xd62f105dL);
l3 = GG(l3, l, l1, l2, al[10], 9L, 0x2441453L);
l2 = GG(l2, l3, l, l1, al[15], 14L, 0xd8a1e681L);
l1 = GG(l1, l2, l3, l, al[4], 20L, 0xe7d3fbc8L);
l = GG(l, l1, l2, l3, al[9], 5L, 0x21e1cde6L);
l3 = GG(l3, l, l1, l2, al[14], 9L, 0xc33707d6L);
l2 = GG(l2, l3, l, l1, al[3], 14L, 0xf4d50d87L);
l1 = GG(l1, l2, l3, l, al[8], 20L, 0x455a14edL);
l = GG(l, l1, l2, l3, al[13], 5L, 0xa9e3e905L);
l3 = GG(l3, l, l1, l2, al[2], 9L, 0xfcefa3f8L);
l2 = GG(l2, l3, l, l1, al[7], 14L, 0x676f02d9L);
l1 = GG(l1, l2, l3, l, al[12], 20L, 0x8d2a4c8aL);
l = HH(l, l1, l2, l3, al[5], 4L, 0xfffa3942L);
l3 = HH(l3, l, l1, l2, al[8], 11L, 0x8771f681L);
l2 = HH(l2, l3, l, l1, al[11], 16L, 0x6d9d6122L);
l1 = HH(l1, l2, l3, l, al[14], 23L, 0xfde5380cL);
l = HH(l, l1, l2, l3, al[1], 4L, 0xa4beea44L);
l3 = HH(l3, l, l1, l2, al[4], 11L, 0x4bdecfa9L);
l2 = HH(l2, l3, l, l1, al[7], 16L, 0xf6bb4b60L);
l1 = HH(l1, l2, l3, l, al[10], 23L, 0xbebfbc70L);
l = HH(l, l1, l2, l3, al[13], 4L, 0x289b7ec6L);
l3 = HH(l3, l, l1, l2, al[0], 11L, 0xeaa127faL);
l2 = HH(l2, l3, l, l1, al[3], 16L, 0xd4ef3085L);
l1 = HH(l1, l2, l3, l, al[6], 23L, 0x4881d05L);
l = HH(l, l1, l2, l3, al[9], 4L, 0xd9d4d039L);
l3 = HH(l3, l, l1, l2, al[12], 11L, 0xe6db99e5L);
l2 = HH(l2, l3, l, l1, al[15], 16L, 0x1fa27cf8L);
l1 = HH(l1, l2, l3, l, al[2], 23L, 0xc4ac5665L);
l = II(l, l1, l2, l3, al[0], 6L, 0xf4292244L);
l3 = II(l3, l, l1, l2, al[7], 10L, 0x432aff97L);
l2 = II(l2, l3, l, l1, al[14], 15L, 0xab9423a7L);
l1 = II(l1, l2, l3, l, al[5], 21L, 0xfc93a039L);
l = II(l, l1, l2, l3, al[12], 6L, 0x655b59c3L);
l3 = II(l3, l, l1, l2, al[3], 10L, 0x8f0ccc92L);
l2 = II(l2, l3, l, l1, al[10], 15L, 0xffeff47dL);
l1 = II(l1, l2, l3, l, al[1], 21L, 0x85845dd1L);
l = II(l, l1, l2, l3, al[8], 6L, 0x6fa87e4fL);
l3 = II(l3, l, l1, l2, al[15], 10L, 0xfe2ce6e0L);
l2 = II(l2, l3, l, l1, al[6], 15L, 0xa3014314L);
l1 = II(l1, l2, l3, l, al[13], 21L, 0x4e0811a1L);
l = II(l, l1, l2, l3, al[4], 6L, 0xf7537e82L);
l3 = II(l3, l, l1, l2, al[11], 10L, 0xbd3af235L);
l2 = II(l2, l3, l, l1, al[2], 15L, 0x2ad7d2bbL);
l1 = II(l1, l2, l3, l, al[9], 21L, 0xeb86d391L);
state[0] += l;
state[1] += l1;
state[2] += l2;
state[3] += l3;
}
private void Encode(byte abyte0[], long al[], int i)
{//转换函数,将al中long型的变量输出到byte型的数组abyte0中,
//低位字节在前,高位字节在后;
int j = 0;
for(int k = 0; k < i; k += 4)
{
abyte0[k] = (byte)(int)(al[j] & 255L);
abyte0[k + 1] = (byte)(int)(al[j] >>> 8 & 255L);
abyte0[k + 2] = (byte)(int)(al[j] >>> 16 & 255L);
abyte0[k + 3] = (byte)(int)(al[j] >>> 24 & 255L);
j++;
}
}
private void Decode(long al[], byte abyte0[], int i)
{
int j = 0;
for(int k = 0; k < i; k += 4)
{
al[j] = b2iu(abyte0[k]) | b2iu(abyte0[k + 1]) << 8 | b2iu(abyte0[k + 2]) << 16 | b2iu(abyte0[k + 3]) << 24;
j++;
}
}
public static long b2iu(byte byte0)
{
return byte0 >= 0 ? byte0 : byte0 & 0xff;
}
public static String byteHEX(byte byte0)
{//字节到十六进制的ASCII码转换
char ac[] = {
'0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
'A', 'B', 'C', 'D', 'E', 'F'
};
char ac1[] = new char[2];
ac1[0] = ac[byte0 >>> 4 & 0xf];
ac1[1] = ac[byte0 & 0xf];
String s = new String(ac1);
return s;
}
public static String toMD5(String s)
{
MD5 md5 = new MD5();
return md5.getMD5ofStr(s);
}
}
public class EncryptPassword { private final static String[] hexDigits = {
"0", "1", "2", "3", "4", "5", "6", "7",
"8", "9", "a", "b", "c", "d", "e", "f"}; /**
* 转换字节数组为16进制字串
* @param b 字节数组
* @return 16进制字串
*/ public static String byteArrayToHexString(byte[] b) {
StringBuffer resultSb = new StringBuffer();
for (int i = 0; i < b.length; i++) {
resultSb.append(byteToHexString(b[i]));
}
return resultSb.toString();
} private static String byteToHexString(byte b) {
int n = b;
if (n < 0)
n = 256 + n;
int d1 = n / 16;
int d2 = n % 16;
return hexDigits[d1] + hexDigits[d2];
} public static String MD5Encode(String origin) {
String resultString = null; try {
resultString=new String(origin);
MessageDigest md = MessageDigest.getInstance("MD5");
resultString=byteArrayToHexString(md.digest(resultString.getBytes()));
}
catch (Exception ex) { }
return resultString;
} public static void main(String[] args){
System.err.println(MD5Encode(""));
System.err.println(MD5Encode("a"));
System.err.println(MD5Encode("abc"));
System.err.println(MD5Encode("message digest"));
System.err.println(MD5Encode("abcdefghijklmnopqrstuvwxyz")); } //MD5 ("") = d41d8cd98f00b204e9800998ecf8427e
//MD5 ("a") = 0cc175b9c0f1b6a831c399e269772661
//MD5 ("abc") = 900150983cd24fb0d6963f7d28e17f72
//MD5 ("message digest") = f96b697d7cb7938d525a2f31aaf161d0
//MD5 ("abcdefghijklmnopqrstuvwxyz") = c3fcd3d76192e4007dfb496cca67e13b}
楼主使用时要记住,MD5是不可逆的,并且有很小的几率产生碰撞。优点是算法速度快,资源耗费小,主要用于文件校验和密码验证,SHA-1也不错!