从页面获取到的价格为 :110.0
numberFormat
java.lang.NumberFormatException: For input string: "110.0"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:456)
at java.lang.Integer.valueOf(Integer.java:553)
at dao.modifyProcess.doGet(modifyProcess.java:61)
at dao.modifyProcess.doPost(modifyProcess.java:97)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:710)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:175)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:844)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447)
at java.lang.Thread.run(Thread.java:619)
null
false

解决方案 »

  1.   

    用Integer.parseInt处理110.0当然不行。
    为什么不直接用Double
      

  2.   

    有小数点的用Double或者Float吧
      

  3.   

    Thanks ,我明白了   
      

  4.   

    110.0是浮点数 用Double的方法
      

  5.   

    1#说的对的说...Integer.parseInt()的时候参数必须为整形
      

  6.   

    shit,知道了也不给分,可怜的那个我啊...
      

  7.   

    Integer.parseInt(String s) 只能处理整形的字符串