得到一个DefaultMutableTreeNode对象，怎么让JTree展开到该节点

Question

该节点的所有父节点都已设置成展开，代码如下：
       top = new DefaultMutableTreeNode(".......");
       createNodeFromDB();
       jTree1=new JTree(top);
       jTree1.setCellRenderer(render);
       jTree1.addTreeExpansionListener(new Dict_District_jTree1_treeExpansionAdapter(this));
       jScrollPaneCenter.getViewport().add(jTree1, null);
       jTree1.putClientProperty("JTree.lineStyle", "Angled");
       jTree1.setShowsRootHandles(true);       TreePath tp_temp=tpSelectedPath;
       int i=tp_temp.getPathCount();
       while(i>0){
           jTree1.expandPath(tp_temp);
System.out.println(tp_temp);
           tp_temp=tp_temp.getParentPath();
           i--;
       }

Answer 1

jTree.expandPath(new TreePath(((DefaultTreeModel)jTree.getModel()).getPathToRoot(node)));