谁能给我一个排序的程序

Question

import javax.swing.*;public class sort{
    public static void main(String[] args){
        String [] str=new String[11];
        //input
        for(int count=1;count<=10;count++)
           str[count]=JOptionPane.showInputDialog
            ("please input the "+count+" String:");
        //sort
        int i=0;
        int j=0;
        for(i=2;i<=10;i++){
            if(str[i]<str[i-1]){
                str[0]=str[i];
                str[i]=str[i-1];
                for(j=i-2;str[0]<str[j];j--)
                    str[j+1]=str[j];
                str[j+1]=str[0];
            }
        }
        //output
        for(int count=1;count<=10;count++)
            System.out.println(count+";"+str[count]);
    }
}

Answer 1

呵呵，java的基础数据结构中就有排序函数啊：）
如：Collection 类的sort()方法就实现了List接口的数据结构排序！
List people = new LinkedList();
Collection.sort(people);
搞定！！

Answer 2

public class sort{
    public static void main(String[] args){
        String [] str=new String[11];
        System.in.readBufferedReader keyboard =
               new BufferedReader(new InputStreamReader(System.in), 1);
        //input
        for(int count=1;count<=10;count++)
           str[count]= keyboard.readLine();}
        //sort
        int i=0;
        int j=0;
        for(i=2;i<=10;i++){
            if(str[i]<str[i-1]){
                str[0]=str[i];
                str[i]=str[i-1];
                for(j=i-2;str[0]<str[j];j--)
                    str[j+1]=str[j];
                str[j+1]=str[0];
            }
        }
        //output
        for(int count=1;count<=10;count++)
            System.out.println(count+";"+str[count]);
    }
}