30分钟写一道程序(C、C++、Java、伪码)，昨天的面试题目!!!

忘记了写代码，I am so sorry......void fun(int n, char A = 'A', char B = 'B', char C='C')
{
  /* 把 n 个盘子从 A 移动到 B，可以借助与 C */
  /* 这就形成了一个递归的过程 */  static stepCount = 0 ;  if ( n > 0 ) {
    fun(n-1, A, C, B);
    cout << "从 " << A << " 移动最顶的盘子到 " << B << endl;
    stepCount++;
    fun(n-1, C, B, A);
  } else {
    cout << "共移动 " << stepCount << " 次" << endl;
  }
}

解决方案 »

免费领取超大流量手机卡，每月29元包185G流量+100分钟通话, 中国电信官方发货

I am sorry......偶看错题目了 ……我做的是把盘子从 A 移到 B，你的题目是从 A 移到 C不过反正 B 和 C 都是空的柱子，数学上是等价的，换一下  BC 的位置就可以了。
汗……在 Java 版发 C 代码，会不会被人打？
ㄻ냐어ㅏㄴ얍ㅈㄷㅈ더잡더ㅏㅈ붇ㅈㅂ더ㅏㅂ저ㅏ로ㅕㅋ
ㄴ얍ㅈㄷㅂ주답저더ㅏㅓ미ㅏㄴ움니ㅏㅓ압저ㅔㄷ재ㅑ벼대ㅑ
퍼ㅑㄹ머ㅏㄴ져ㅑㅛㄷㅂ저ㅏ더자ㅏㅓㄴ아미;ㅏ니암이ㅏㅁ니;아
코렴너암너ㅈ바더쟈ㅂ뎌ㅏㄹ라ㅓ캬ㅐㅕㅁㄴ어ㅏㅣㅏ비;자뎌ㅗ카ㅜ
f(n) = 2*f(n-1) + 1
public class Card {
    private int suit = UNASSIGNED;
    private int number = UNASSIGNED;    public final static int UNASSIGNED = -1;    public final static int DIAMONDS = 1;
    public final static int CLUBS = 2;
    public final static int HEARTS = 3;
    public final static int SPADES = 4;    public final static int ACE = 1;
    public final static int KING = 13;    public Card(int number, int suit) {
        if (isValidNumber(number)) {
            this.number = number;
        } else {
            //Error
        }        if (isValidSuit(suit)) {
            this.suit = suit;
        } else {
            //Error
        }
    }    public int getSuit() {
        return suit;
    }    public int getNumber() {
        return number;
    }    public static boolean isValidNumber(int number) {
        if (number >= ACE && number <= KING) {
            return true;
        } else {
            return false;
        }
    }
    public static boolean isValidSuit(int suit) {
        if (suit >= DIAMONDS && suit <= SPADES) {
            return true;
        } else {
            return false;
        }
    }    public static String numberToString(int number) {
        String result = "";
        switch (number) {
            case ACE: result =  "Ace"; break;
            case 2: result = "Two"; break;
            case 3: result = "Three"; break;
            case 4: result = "Four"; break;
            case 5: result = "Five"; break;
            case 6: result = "Six"; break;
            case 7: result = "Seven"; break;
            case 8: result = "Eight"; break;
            case 9: result = "Nine"; break;
            case 10: result = "Ten"; break;
            case 11: result = "Jack"; break;
            case 12: result = "Queen"; break;
            case KING: result = "King"; break;
            case UNASSIGNED: result = "Invalid Number"; break;
        }
        return result;
    }    public static String suitToString(int suit) {
        String result = "";
        switch (suit) {
            case DIAMONDS: result = "Diamonds"; break;
            case CLUBS: result = "Clubs"; break;
            case HEARTS: result = "Hearts"; break;
            case SPADES: result = "Spades"; break;
            case UNASSIGNED: result = "Invalid Suit"; break;
        }
        return result;
    }
}
可惜不是这个
public class Deck {    public static int numSuits = 4;
    public static int numCardsPerSuit = 13;
    public static int numCards = numSuits * numCardsPerSuit;    private Card[][] cards;    public Deck() {
        cards = new Card[numSuits][numCardsPerSuit];
        for (int suit = Card.DIAMONDS; suit <= Card.SPADES; suit++) {
            for (int number = Card.ACE; number <= Card.KING; number++) {
                cards[suit-1][number-1] = new Card(number, suit);
            }
        }
    }
    public Card getCard(int suit, int number) {
        return cards[suit-1][number-1];
    }
}
这是什么你猜
public class DisplayDeck {
    public static void main(String[] args) {
        Deck deck = new Deck();
        for (int suit = Card.DIAMONDS; suit <= Card.SPADES; suit++) {
            for (int number = Card.ACE; number <= Card.KING; number++) {
                Card card = deck.getCard(suit, number);
                System.out.println(card.numberToString(card.getNumber())
                                   + " of "
                                   + card.suitToString(card.getSuit()));
            }
        }
    }
}
是牌,
integer i;public void hhh(integer n;char a,b,c){
if(n>0){
        hhh(n-1,a,c,b);
        i = i +1 ;
        jTextArea1.append(String.valueof(i)+':  Move '+a+' to '+c);
        hhh(n-1,b,a,c);
}}public void get_count(integer n){
char a,b,c;
a='A';  b='B'; c='C';
i = 0;
hhh(n,a,b,c);
//得出总次数i
}
此问题我已经解决，java代码如下：public class HanNuoTa
{
public static void hanoi(int n,String start,String middle,String end)
{
//终止条件，移动一个盘子
if (n==1)
System.out.println("Move " + start + " To " + end);
//将n-1个盘子移到"middle"，将第一个盘子移到"end"
//再将n-1个盘子从"middle"移到"end"
else
{
hanoi(n-1,start,end,middle);
System.out.println("Move " + start + " to " + end);
hanoi(n-1,middle,start,end);
}
}

public static void main(String[] args)
{
//盘子个数和各个柱子的名字
int n = 3;
String start = "start";
String middle = "middle";
String end = "end";
//输入盘子的个数和n个盘子的移动方法
/*System.out.print("Enter the numbers of disks: ");
try
{
n = System.in.read();
}
catch(Exception ex)
{
System.out.println("The number is wrong: " + ex);
}
                  */
System.out.println("The solution for n = " + n + " :");
hanoi(n,start,middle,end);
}

}运行程序可看出具体的移动过程，n可以修改，也可以由键盘输入，如果要知道次数，可加一个static变量
谢谢各位了