求问一个分割方法. -- 把特定字符之间的字符剥离出来.

Question

条件:
<img src=\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\"><img src=\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\">
分离后想得到的结果:
String[] sArray={"jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\","jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\"};求思路, 源码, 或者高效方法.

Answer 1

这里真是个神奇的地方, 我都憋了三天没干出来, 这会居然想到了.....自己贴个解决办法youtData="<img src=\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\"><img src=\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\">";

String[] tmp=youtData.split("<img");

List<String> l=new ArrayList<String>();

Pattern pattern = Pattern.compile("src=\"data:(.*)\">");

for(int i=0;i<tmp.length;i++)
{
Matcher matcher = pattern.matcher(tmp[i]);
if(matcher.find())
{
System.out.println(matcher.group(1));
}
}
求更好的思路.

Answer 2

import java.util.LinkedList;
import java.util.List;public class Hello {
    public static void main(String[] args) throws Exception {
        String[] strs = {
                "<img src=\\\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\\\">",
                "<img src=\\\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\\\">"
        };        List<String> result = new LinkedList<String>();        String pattern = "<img src=\\\\\"data:image/(.+)\">";
        for (int i = 0; i < strs.length; ++i) {
            result.add(strs[i].replaceAll(pattern, "$1"));
        }        System.out.println(result);
    }
}输出
[jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\, jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\]

Answer 3

注意正则里有贪婪与非贪婪模式: +与+?
import java.util.regex.Matcher;
import java.util.regex.Pattern;public class Hello {
    public static void main(String[] args) throws Exception {
        String str =
                "<img src=\\\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\\\"><img src=\\\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\\\">"
        ;        String patternString = "<img src=\\\\\"data:image/(.+?)\">";
        Pattern pattern = Pattern.compile(patternString);
        Matcher matcher = pattern.matcher(str);        while (matcher.find()) {
            System.out.println(matcher.group(1));
        }
    }
}
输出
jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\
jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\

Answer 4

首先楼主的代码是换行的
所以使用正则时必须添加忽视换行的不爱护(?s)。
楼主这活我以前经常干，从人家网站抓图片下载到本地。。String btnstr="<img src=\"data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAgGBgcGBQgHBwcJCQgKDBQNDAOijjEUYRScD1ooooA//Z\">";
Pattern p=Pattern.compile("(?s)img src=\"data:image/(jpeg.*?)\"");//这里最后一个\不会截取，因为输入字符串中其实本身就没有"\"
Matcher m=p.matcher(btnstr);
while(m.find()){
System.out.println(m.group(1));
}