帮看一段简单的代码

Question

本帖最后由 yaojianquansb 于 2010-07-29 00:15:03 编辑

Answer 1

import java.util.LinkedList;
public class Test  extends Thread{
        static LinkedList<String> myList = new LinkedList<String>();
        static  boolean flag=true;
        public Test(){}
        public Test(String threadName){
                super(threadName);
        }
        public static void add(){
              myList.add("apple1");
              myList.add("apple2");                  
              flag=false;
        }
        public void run(){                
                synchronized(myList){
                        try{
                        while(myList.size()==0){
                        if(flag)
                              {System.out.println("Warnning:"+getName()+" It's empty!");
                                myList.wait();}
                         else 
                             break;
                         
                          }
                         if(myList.size()>0) 
                        {String s = myList.removeLast();
                       System.out.println(getName()+":"+s);}
                      else
                         System.out.println("INFO:"+getName()+" quit.");
                    }catch(Exception e){
                        e.printStackTrace();
                    }
                }
        }
        public static void main(String args[]){        
              Test t1 = new Test("t1");
              Test t2 = new Test46("t2");
                      Test46 t3 = new Test("t3");
                t1.start();
                t2.start();
                t3.start();
                try{
                    Thread.sleep(3000);
                }catch(Exception e){
                      e.getMessage();
                }
                synchronized(myList){                
                        add();
                        myList.notifyAll();
                }
        }
}

Answer 2

这是简单的生产者与消费者问题， 只不过没有生产者，
是不是可以当myList.size()==0时就退出，因为此时没有生产者，那么对于消费者来说wait()就没什么意义，
LZ看下是不是可以这样:
while(myList.size()==0){
                              System.out.println("Warnning:"+getName()+" It's empty!");
                               // myList.wait();
break;
                        }

Answer 3

士兵突击  麻烦看一下这个，http://topic.csdn.net/u/20100729/15/232335a5-4632-4501-b899-a249750dd22f.html?10290，我昨天想问这个的，后来自己写了个简单点的，悟性太低，这个明白了，那个还是不会。