找到xml里面的所有某个名称的标签

Question

用xpath实现
需要用到dom4j.jar和jaxen.jar        StringBuilder builder = new StringBuilder();
        SAXReader saxReader = new SAXReader();
        Document document = saxReader.read(new File(""));
        Element root = document.getRootElement();
        List<Element> list = root.selectNodes("//resource");
        for (Element e : list) {
            builder.append(e.attributeValue("name")).append(",");
        }

Answer 1

Document doc = sax.build("test.xml");  
            Element rootEle = doc.getRootElement();                          
            List resourcesList = XPath.selectNodes(rootEle, "//resources/resource");  
// 循环list

Answer 2

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(false);
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("src/test.xml");
XPathFactory xFactory = XPathFactory.newInstance();
XPath xpath = xFactory.newXPath();
XPathExpression expr = xpath.compile("//resource/@name");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
for (int i = 0; i < nodes.getLength(); i++) {
System.out.println(nodes.item(i).getTextContent());
}xpath

Answer 3

不知道导入哪个类，能不能把 import 部分也贴出来啊

Answer 4

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;import org.w3c.dom.Document;
import org.w3c.dom.NodeList;

Answer 5

运行成功 但是好像结果是空的
builder就是你要的值，可以用builder.toString()转换为字符串。