求数字大小写转换的java程序

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import   java.text.DecimalFormat; /**
  *   小写金额转换大写金额
  *   @author   Lucky   &   Ryan
  */
public   class   ChnAmt
{
private   String[]   saChnAmount   =   new   String[50];
private   int   iArrayLen   =   0;
private   int   iArrayPos   =   0; /**
  *   构造-小写金额转换大写对象(不带参)
  *   @param String sAmount
  */
public   ChnAmt(   String   sAmount   )   {
int   iDecFrac   =   0; if   (   sAmount.indexOf(   ". "   )   !=   -1   )   {
iDecFrac   =   sAmount.length()   -   sAmount.indexOf(   ". "   );
if   (   iDecFrac   >   3   )   {
iDecFrac   =   3;
}
sAmount   =   sAmount.substring(   0,   sAmount.indexOf(   ". "   )   )
+   sAmount.substring(   sAmount.indexOf(   ". "   )   +   1,   sAmount.indexOf(   ". "   )   +   iDecFrac   );
for   (   ;   iDecFrac   <   3;   iDecFrac++   )   {
sAmount   +=   "0 ";
}
}   else   {
sAmount   +=   "00 ";
} toChnAmt(   sAmount,   2,   false   );
}
/**
  *   构造-小写金额转换大写对象(带参)
  *   @param String sAmount
  *   @param int iDec
  *   @param boolean bDot
  */
public   ChnAmt(   String   sAmount,   int   iDec,   boolean   bDot   )   {
if   (   bDot   )   {
if   (   sAmount.indexOf(   ". "   )   <   0   )   {
//   没有小数点
sAmount   +=   ". ";
for   (   int   iFor   =   iDec;   iFor   >   0;   iFor--   )   {
sAmount   +=   "0 ";
}
}   else   {
int   iDecLen   =   sAmount.length()   -   sAmount.indexOf(   ". "   )   -   1   ;
if   (   iDecLen   >   iDec   )   {
//   去位
sAmount   =   sAmount.substring(   0,   sAmount.indexOf(   ". "   )   +   iDec   +   1   );
}   else   if   (   iDecLen   <   iDec   )   {
//   补零
for   (   int   iFor   =   iDec   -   iDecLen;   iFor   >   0;   iFor--   )   {
sAmount   +=   "0 ";
}
}
}
}
toChnAmt(   sAmount,   iDec,   bDot   );
} /**
  *   小写金额转换大写
  *   @param String sAmount
  *   @param int iDec
  *   @param boolean bDot
  */
public   void   toChnAmt(   String   sAmount,   int   iDec,   boolean   bDot   )   {
//   数字
final   String   []   sUserCode   =   { "零 ",   "壹 ",   "贰 ",   "叁 ",   "肆 ",   "伍 ",   "陆 ",   "柒 ",   "捌 ",   "玖 "   };
//   单位
final   String   []   sChnUnit     =   { "厘 ", "分 ", "角 ", "元 ", "十 ", "百 ", "千 ", "万 ", "十 ", "百 ", "千 ", "亿 ", "十 ", "百 ", "千 ", "万 "};
//   整
final   String   sSpecEnd   =   "整 ";
//   标志
//   '9 '代表十
//   '3 '   -   '元 ',   '1 '   -   '万 '(   如遇前一生成字符为 '亿 '，则不生成 '万 '   ),   '3 '   -   '亿 '
//   '0 '   -   其他
final   byte   []   byFlag   =   { 0, 0, 0, 3, 9, 0, 0, 1, 9, 0, 0, 3, 9, 0, 0, 0   }; int   iCounter,   iPos;
byte   byPreFlag=-1;
char   cDigit,   cPreDigit= '   '; iArrayLen   =   0; switch   (   iDec   )   {
//   补零
case   0:
sAmount   +=   "0 ";
case   1:
sAmount   +=   "0 ";
case   2:
sAmount   +=   "0 ";
case   3:
break;
default:
sAmount   =   sAmount.substring(0,sAmount.length()-iDec   +   3)   ;
} if   (   bDot   )   {
//   转换小数点
sAmount   =   sAmount.substring(0,sAmount.length()-4   )   +   sAmount.substring(sAmount.length()-3   );
} //   开始转换
for(   iCounter=sAmount.length()   ;   iCounter> 0;   iCounter--)
{
//   计算数字位置
iPos   =   sAmount.length()   -   iCounter;
//   获得数字字符
cDigit   =   sAmount.charAt(iPos); //   过滤数字
if   (   cDigit < '0 '   ||   cDigit> '9 '   )   cDigit   =   '0 '; if   (   cDigit   !=   '0 '   )   {
//   当前数字不为 '0 '
if   (   cPreDigit   ==   '0 '   )   {
//   前一数字为 '0 '
if   (   byPreFlag   !=   3   &&   byPreFlag   !=   1   )   {
//   '亿 '， '万 '， '元 '   后不加   '零 '
saChnAmount[   ++iArrayLen   ]   =   sUserCode[   0   ];
}
} if   (   cDigit   == '1 '   &&   byFlag[iCounter-1]   ==   9   &&   iArrayLen   ==   0   )   {
//   数字为 '1 '，单位为 '十 '，且为第一个数字时，不报 '1 '，只报 '十 '
saChnAmount[   ++iArrayLen   ]   =   sChnUnit[   iCounter   -   1   ];
}   else   {
//   生成数字
saChnAmount[   ++iArrayLen   ]   =   sUserCode[   Character.digit(   cDigit,   10   )   ];
//   生成单位
saChnAmount[   ++iArrayLen   ]   =   sChnUnit[   iCounter   -   1   ]; //   记录当前位标志
byPreFlag   =   byFlag[iCounter-1];
}
}   else   {
//   数字为 '0 '
if   (   iArrayLen   ==   0   )   {
//   过滤首位 '0 '
continue;
}   else   {
if   (   byFlag[iCounter-1]   ==   3   ||   (   byFlag[iCounter-1]==1   &&   byPreFlag!=3   &&   !saChnAmount[   iArrayLen   ].equals(   sChnUnit[   11   ]   )   )   )   {
//   生成 '亿 '， '万 '， '元 '的单位，但如果从 '千万 '位到 '万 '位都为0，则不生成 '万 '
saChnAmount[   ++iArrayLen   ]   =   sChnUnit[   iCounter   -   1   ];
}
//   记录当前位标志
byPreFlag   =   byFlag[iCounter-1];
}
} //   记录当前数字
cPreDigit   =   cDigit;
} if   (   iArrayLen   ==   0   )   {
//   转换结束数组长度为0，生成 '0元整 '
saChnAmount[   ++iArrayLen   ]   =   sUserCode[   0   ];
saChnAmount[   ++iArrayLen   ]   =   sChnUnit[   3   ];
saChnAmount[   ++iArrayLen   ]   =   sSpecEnd;
} if   (   saChnAmount[   iArrayLen   ].equals(   sChnUnit[   3   ]   )   )   {
//   最后位为 '元 '，加上 '整 '
saChnAmount[   ++iArrayLen   ]   =   sSpecEnd;
} } /**
  *   判断是否还有下一个转换元素
  *   @return boolean
  */
public   boolean   next()   {
boolean   bRtn   =   false; if   (   iArrayPos++   <   iArrayLen   )   {
bRtn   =   true;
}
return   bRtn; } /**
  *   获取当前转换元素
  *   @return String
  */
public   String   getResult()   {
String   sRtn   =   " "; sRtn   =   saChnAmount[   iArrayPos   ]; return   sRtn;
} /**
  *   转换double到String
  *   @param double dMoney
  *   @return String
  */
public   static   String   Double2String(   double   dMoney   )   {
String   sMoney   =   " "; DecimalFormat   df   =   new   DecimalFormat(   "############.### "   );
try   {
sMoney   =   df.format(   dMoney   );
}   catch   (   Exception   e   )   {
sMoney   =   " ";
} return   sMoney;
} public   static   void   main(   String   []   sArgv   )
{
ChnAmt   chnAMT   ; chnAMT   =   new   ChnAmt( "936.00 "); System.out.println(   "ChnAmt()   [936.00]   to   "   ); while(   chnAMT.next()   )
{
System.out.println(   "Value[ "   +   chnAMT.getResult()   +   "] "   );
}
}
}

我没提到数据库啊，映射表是放在内存中的，hashmap是不错的选择

这是我写的一个小写转换成大写的程序，能实现亿以上位数的转换：两个java文件，Big.java和Io.java
Big.java如下：
import java.util.*;
public class Big {

public static void main(String[] args)
{ Scanner sc=new Scanner(System.in);

String i=sc.nextLine();
io io =new io();
String t="";
int m=0; //让其进行两次循环，先整数后小数
int sr=0;
StringTokenizer st=new StringTokenizer(i,".");//用点分割
while(st.hasMoreTokens())
{
String nt=st.nextToken();
int n=nt.length();
sr=n-1;
if(m==0) //对整数部分的执行

{ //m++;
while(n>0)
{ n--; char c=nt.charAt(sr-n);
if(n>=5&&n<8)
{
//m=0;
t=io.bigWriter(c, t);
t=io.smallWriter(n,t);
continue;
}else if(n>=8)
{
m=0;
t=io.bigWriter(c, t);
t=io.smallWriter(n,t);
continue;
}
t=io.bigWriter(c,t);

t=io.smallWriter(n,t);
}
}
else //对小数部分的执行
{

while(n>0)
{
n--;
char c=nt.charAt(1-n);
if(c=='0'&&(nt.charAt(1)=='0'))
{
System.out.println(t+"整");
return;
}

t=io.bigWriter(c,t);

if(n==1)
t=t+"角";
else if(n==0)
{
t=t+"分";
}else
{
System.out.println("输入有误");
return;
}
}
}

}
System.out.print(t);
}

}
Io.java 如下：public class Io {
       public String bigWriter(char c,String t)
       {
     switch (c)
{
case '0':
t=t+"零";
break;
case '1':
t=t+"壹";
break;
case '2':
t=t+"贰";
break;
case '3':
t=t+"叁";
break;
case '4':
t=t+"肆";
break;
case '5':
t=t+"伍";
break;
case '6':
t=t+"陆";
break;
case '7':
t=t+"柒";
break;
case '8':
t=t+"捌";
break;
case '9':
t=t+"氿";
break;

}
        return t;

       }
       public String smallWriter(int n ,String t)
       {
     if(n>=5&&n<8)
{
if(n==5)
t=t+"拾";
else if(n==6)
t=t+"佰";
else if (n==7)
t=t+"仟";
//System.out.print("qqqqqqqqqq");
}
     else if(n>=8)
     {
     if(n==8)
t=t+"亿";
else if(n==9)
t=t+"拾";
else if (n==10)
t=t+"佰";
else if(n==11)
t=t+"仟";
else if(n==12)
t=t+"万";
     }
     else if(n==4)
     t=t+"万";
else if(n==3)
t=t+"仟";
else if(n==2)
t=t+"佰";
else if(n==1)
t=t+"拾";
else if(n==0)
{
t=t+"元";
}else
{
System.out.println("输入有误1");
}
        return t;

       }
}
希望对你有帮助

支持一楼，Google查查，能找到的

package houlei.csdn.text;public class RMBReader { static char [] nums = new char [] {'零','壹','贰','叁','肆','伍','陆','柒','捌','玖'};
static char [] units = new char [] {'\0','拾','佰','仟','万','拾','佰','仟','亿','拾','佰','仟','万','拾','佰','仟'};

public static String convert(String number){
String [] sub = number.split("\\.");
if(sub.length<=0 || sub.length>2)throw new NumberFormatException("数字格式有误");
StringBuilder buff = new StringBuilder();
convertInteger(sub[0],buff);
if(sub.length==2){
buff.append("点");
convertFloat(sub[1],buff);
}
return buff.toString();
}

private static void convertFloat(String floatString, StringBuilder buff) {
char floatNums [] = floatString.toCharArray();
for(char ch : floatNums){
buff.append(nums[ch-'0']);
}
} private static void convertInteger(String intString, StringBuilder buff) {
char intNumbs [] = intString.toCharArray();
if(intNumbs.length<=0){
buff.append(nums[0]);
return;
}
for(int i=intNumbs.length-1;i>=0;i--){
if(intNumbs[i]!='0'){
buff.insert(0,nums[intNumbs[i]-'0']);
}else{
if(buff.length()>0 && buff.charAt(0)!=nums[0])buff.insert(0, nums[0]);
}
int unit = intNumbs.length-i-1;
if(unit<=0 || intNumbs[i]=='0')continue;
buff.insert(1,units[unit]);
}
} /**
* @param args
*/
public static void main(String[] args) {
System.out.println(convert("1009.168"));
}}

调试易

求数字大小写转换的java程序

解决方案 »