现有字符串 where="FASJ >= TO_DATE('2010-01-22 14:01:48','YYYY-MM-DD HH24:MI:SS') And
FASJ <= TO_DATE('2010-04-22 14:01:48','YYYY-MM-DD HH24:MI:SS')
And PCSBM in ('130200000000','130202180000','130202190000') 我想在servlet里面解析出 里面的时间字符,也就是2010-01-22 14:01:48 和 2010-04-22 14:01:48 ,可有什么好办法
FASJ <= TO_DATE('2010-04-22 14:01:48','YYYY-MM-DD HH24:MI:SS')
And PCSBM in ('130200000000','130202180000','130202190000') 我想在servlet里面解析出 里面的时间字符,也就是2010-01-22 14:01:48 和 2010-04-22 14:01:48 ,可有什么好办法
.matcher("你的字符串"); while(m.find()){
System.out.println(m.group());
}
String S3 = "where FASJ >= TO_DATE('2010-01-22 14:01:48','YYYY-MM-DD HH24:MI:SS') And FASJ <= TO_DATE('2010-04-22 14:01:48','YYYY-MM-DD HH24:MI:SS') And PCSBM in ('130200000000','130202180000','130202190000')"; Pattern p = Pattern.compile("\\d{4}-\\d{2}-\\d{2} \\d{2}:\\d{2}:\\d{2}");
Matcher m = p.matcher(S3);
int index = 0;
while (m.find()){
index++;
System.out.println("INDEX: " + index);
String str1 = m.group();
System.out.println("group: [" + str1 + "]");
}
}