java 输入流问题

Question

System.out.println("请输入...");                
byte[] buffer = new byte[1024];                 
System.in.read(buffer);                         
System.out.println("");                         
System.out.println("");                         
System.out.println("你输入的内容：");             
System.out.println(new String(buffer,"gb2312"));

Answer 1

不好意思,我的程序里需要多次输入数据System.out.println("请输入...");                
byte[] buffer = new byte[1024];                 
System.in.read(buffer);                         
System.out.println("");                         
System.out.println("");                         
System.out.println("你输入的内容：");             
System.out.println(new String(buffer,"gb2312"));System.out.println("请输入...");                System.in.read(buffer);                         
System.out.println("");                         
System.out.println("");                         
System.out.println("你输入的内容：");             
System.out.println(new String(buffer,"gb2312"));在第二次输入后输出的内容就不对了

Answer 2

public class Test58 {
  //String h="Hello the world.";
  public Test58(){
    try{
      System.out.println("请输入：");      byte[] buffer = new byte[1024];
      System.in.read(buffer);
      System.out.println("\n"+new String(buffer,0,buffer.length));
      System.out.println("请输入：");      System.in.read(buffer);
      System.out.println("\n"+new String(buffer,0,buffer.length));    }
    catch(IOException e){
      e.printStackTrace();
    }
  }  public  static void main(String[] args){
    new Test58();
  }
}

Answer 3

int v = Integer.parseInt(buffer);