有个比较笨点的：
判断每个字符,然后条件if(c.equals("1")){.....}
依此类推。
判断每个字符,然后条件if(c.equals("1")){.....}
依此类推。
解决方案 »
- java或者C# 字符串 转byte[]
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- tomcat的web-inf/classes下编译.java的问题，憋了很久了，希望好心人来看看！！100分相送！！
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- 请问Class.getMethod()方法问题
- [求助]如何把DOS提示符从"c:\"更改为"java>"?
public static String numtochinese(String input){
String s1="零壹贰叁肆伍陆柒捌玖";
String s4="分角整元拾佰仟万拾佰仟亿拾佰仟";
String temp="";
String result="";
if (input==null) return "输入字串不是数字串只能包括以下字符（'0'～'9'，'.')，输入字串最大只能精确到仟亿，小数点只能两位！";
temp=input.trim();
float f;
try{
f=Float.parseFloat(temp); }catch(Exception e){return "输入字串不是数字串只能包括以下字符（'0'～'9'，'.')，输入字串最大只能精确到仟亿，小数点只能两位！";}
int len=0;
if (temp.indexOf(".")==-1) len=temp.length();
else len=temp.indexOf(".");
if(len>s4.length()-3) return("输入字串最大只能精确到仟亿，小数点只能两位！");
int n1,n2=0;
String num="";
String unit=""; for(int i=0;i<temp.length();i++){
if(i>len+2){break;}
if(i==len) {continue;}
n1=Integer.parseInt(String.valueOf(temp.charAt(i)));
num=s1.substring(n1,n1+1);
n1=len-i+2;
unit=s4.substring(n1,n1+1);
result=result.concat(num).concat(unit);
}
if ((len==temp.length())||(len==temp.length()-1)) result=result.concat("整");
if (len==temp.length()-2) result=result.concat("零分");
return result;
}
2、（JSP）
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<meta name="GENERATOR" content="Microsoft FrontPage 4.0">
<meta name="ProgId" content="FrontPage.Editor.Document">
<title>转换大写金额</title>
<STYLE type=text/css>
INPUT { BORDER-RIGHT: #c0d3dc 1px solid; BORDER-TOP: #c0d3dc 1px solid; BORDER-LEFT: #c0d3dc 1px solid; BORDER-BOTTOM: #c0d3dc 1px solid; font-family: verdana; HEIGHT: 19px}
BODY {font-family:arial,helvetica,Tahoma; font-size: 9pt; color:'094A82'}
</STYLE>
<bgsound id=bgsoundone src="" loop=1>
</head>
<body>
<SCRIPT LANGUAGE="VBScript">
dim hj,hji
sub document_onkeypress()
if window.event.srcelement.id="num" and window.event.keycode="13" then
call retu_cn()
end if
end sub
sub window_onload()
document.fmSubmit.t1.focus()
end sub
SUB retu_cn()
dim n,m_hj,s,ch,ch2,ch3,num
num=Replace(trim(document.fmSubmit.t1.value),",","",1,-1,1)
if num="" then
MsgBox "您还没有输入金额！"
document.fmSubmit.t1.focus()
exit sub
End If
if IsNumeric(num)=False then
MsgBox "您输入的不是金额！"
document.fmSubmit.t1.focus()
exit sub
End If
n=FormatNumber(num,2,-1)
num=n
n=Replace(n,",","",1,-1,1)
If len(n)>15 Then
MsgBox "金额必须小于千亿！"
document.fmSubmit.t1.focus()
exit sub
End If
hj=space(0)
s="840"
ch="壹贰叁肆伍陆柒捌玖"
ch2="仟佰拾 "
ch3="亿万元"
for x=1 to 3
m=cstr(int(n/10^FormatNumber(mid(s,x,1),0,-1)))
m=space(4-len(m))+m
m_hj=space(0)
if m<>" 0" then
for y=1 to 4
if mid(m,y,1)<>space(1) and mid(m,y,1)<>"0" then
m_hj=trim(m_hj+mid(ch,FormatNumber(mid(m,y,1),0,-1),1)+mid(ch2,y,1))
else
if mid(m,y,1)=space(1) or mid(m,y,1)="0" then
m_hj=m_hj
if right(m_hj,1)="零" then
m_hj=m_hj+space(0)
else
m_hj=m_hj+"零"
end if
else
m_hj=m_hj
end if
end if
next
if right(m_hj,1)="零" then
m_hj=mid(m_hj,1,len(m_hj)-1)+mid(ch3,x,1)
if x=3 then
m_hj=m_hj+space(0)
else
m_hj=m_hj+"零"
end if
else
m_hj=m_hj+mid(ch3,x,1)
end if
if right(hj,1)="零" and mid(m_hj,1,1)="零" then
hj=hj+mid(m_hj,2,len(m_hj)-1)
else
hj=hj+m_hj
end if
else
if x=3 then
if right(hj,1)="零" then
if trim(hj)="零" then
hj=hj+space(0)
else
hj=mid(hj,1,len(hj)-1)+"元"
end if
else
if trim(hj)="零" then
hj=hj+space(0)
else
hj=hj+"元"
end if
end if
else
if right(hj,1)="零" then
hj=hj+space(0)
else
hj=hj+"零"
end if
end if
end if
if n-int(n)=0 then
n=n-int(FormatNumber(m,0,-1))*10^int(FormatNumber(mid(s,x,1),0,-1))
else
tt=FormatNumber("0."+mid(cstr(n),Instr(1,n,".")+1,2),2)
n=int(n)
n=n-int(FormatNumber(m,0,-1))*10^int(FormatNumber(mid(s,x,1),0,-1))
n=n+tt
end if
next
m=mid(cstr(n),2,2)
if trim(len(m))<>2 then
m=m+"0"
end if
if n*100=0 then
if left(hj,1)="零" then
if right(hj,1)="零" then
hj=hj+"元整"
else
hj=mid(hj,2,len(hj)-1)+"整"
end if
else
if right(hj,1)="零" then
hj=mid(hj,1,len(hj)-1)+"整"
else
hj=hj+"整"
end if
end if
else
if right(hj,1)="零" then
hj=mid(hj,1,len(hj)-1)
else
hj=hj
end if
if mid(m,1,1)="0" or mid(m,1,1)=space(1) then
hj=hj+"零"
else
hj=hj+mid(ch,FormatNumber(mid(m,1,1),0,-1),1)+"角"
end if
if mid(hj,1,1)="零" then
hj=mid(hj,2,len(hj)-1)
else
hj=hj
end if
if mid(m,2,1)="0" then
hj=hj+"整"
else
hj=hj+mid(ch,FormatNumber(mid(m,2,1),0,-1),1)+"分"
end if
end if
if num=".00" then
document.fmSubmit.t1.value="0.00"
else
document.fmSubmit.t1.value=num
end if
document.fmSubmit.t2.value=""
hji=1
call read()
End Sub
SUB read()
MyVar=mid(hj,hji,1)
document.fmSubmit.t2.value=document.fmSubmit.t2.value+MyVar
Select Case MyVar
Case "零" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/0.wav"
Case "壹" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/1.wav"
Case "贰" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/2.wav"
Case "叁" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/3.wav"
Case "肆" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/4.wav"
Case "伍" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/5.wav"
Case "陆" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/6.wav"
Case "柒" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/7.wav"
Case "捌" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/8.wav"
Case "玖" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/9.wav"
Case "拾" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/10.wav"
Case "佰" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/b.wav"
Case "仟" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/q.wav"
Case "万" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/w.wav"
Case "亿" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/y.wav"
Case "元" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/yuan.wav"
Case "分" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/fen.wav"
Case "角" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/jiao.wav"
Case "整" document.all("bgsoundone").src="http://go.163.com/yjsj/wav/z.wav"
Case else hji=0
document.all("bgsoundone").src=""
exit sub
End Select
hji=hji+1
setTimeout "read",400
End Sub
</script>
最完整、最标准的大写金额转换程序，特别是“零”和“整”的转换，最大金额可到仟亿。
<br/>
并加入了朗读功能，所以说是最完美的大写金额转换程序！
<br/>
<form id=fmSubmit name=fmSubmit method="POST">
<p>请
{
var intFen,i;
var strArr,strCheck,strFen,strDW,strNum,strBig,strNow; if(trim(value)=="") //数据为空时返回"零"
return "零";
if (isNaN(value)) //数据非法时提示，并返回空串
{
strErr = "数据"+value+"非法！"
alert(strErr);
return "";
}
strCheck = value+".";
strArr = strCheck.split(".");
strCheck = strArr[0];
if(strCheck.length>12) //数据大于等于一万亿时提示无法处理
{
strErr = "数据"+value+"过大，无法处理！"
alert(strErr);
return "";
}
try
{
i = 0;
strBig = "";
intFen = value*100; //转换为以分为单位的数值
strFen = intFen.toString();
strArr = strFen.split(".");
strFen = strArr[0];
intFen = strFen.length; //获取长度
strArr = strFen.split(""); //将各个数值分解到数组内
while(intFen!=0) //分解并转换
{
i = i+1;
switch(i) //选择单位
{
case 1:strDW = "分";break;
case 2:strDW = "角";break;
case 3:strDW = "元";break;
case 4:strDW = "拾";break;
case 5:strDW = "佰";break;
case 6:strDW = "仟";break;
case 7:strDW = "万";break;
case 8:strDW = "拾";break;
case 9:strDW = "佰";break;
case 10:strDW = "仟";break;
case 11:strDW = "亿";break;
case 12:strDW = "拾";break;
case 13:strDW = "佰";break;
case 14:strDW = "仟";break;
}
switch (strArr[intFen-1]) //选择数字
{
case "1":strNum = "壹";break;
case "2":strNum = "贰";break;
case "3":strNum = "叁";break;
case "4":strNum = "肆";break;
case "5":strNum = "伍";break;
case "6":strNum = "陆";break;
case "7":strNum = "柒";break;
case "8":strNum = "捌";break;
case "9":strNum = "玖";break;
case "0":strNum = "零";break;
} //处理特殊情况
strNow = strBig.split("");
//分为零时的情况
if((i==1)&&(strArr[intFen-1]=="0"))
strBig = "整";
//角为零时的情况
else if((i==2)&&(strArr[intFen-1]=="0"))
{ //角分同时为零时的情况
if(strBig!="整")
strBig = "零"+strBig;
}
//元为零的情况
else if((i==3)&&(strArr[intFen-1]=="0"))
strBig = "元"+strBig;
//拾－仟中一位为零且其前一位（元以上）不为零的情况时补零
else if((i<7)&&(i>3)&&(strArr[intFen-1]=="0")&&(strNow[0]!="零")&&(strNow[0]!="元"))
strBig = "零"+strBig;
//拾－仟中一位为零且其前一位（元以上）也为零的情况时跨过
else if((i<7)&&(i>3)&&(strArr[intFen-1]=="0")&&(strNow[0]=="零"))
{}
//拾－仟中一位为零且其前一位是元且为零的情况时跨过
else if((i<7)&&(i>3)&&(strArr[intFen-1]=="0")&&(strNow[0]=="元"))
{}
//当万为零时必须补上万字
else if((i==7)&&(strArr[intFen-1]=="0"))
strBig ="万"+strBig;
//拾万－仟万中一位为零且其前一位（万以上）不为零的情况时补零
else if((i<11)&&(i>7)&&(strArr[intFen-1]=="0")&&(strNow[0]!="零")&&(strNow[0]!="万"))
strBig = "零"+strBig;
//拾万－仟万中一位为零且其前一位（万以上）也为零的情况时跨过
else if((i<11)&&(i>7)&&(strArr[intFen-1]=="0")&&(strNow[0]=="万"))
{}
//拾万－仟万中一位为零且其前一位为万位且为零的情况时跨过
else if((i<11)&&(i>7)&&(strArr[intFen-1]=="0")&&(strNow[0]=="零"))
{}
//万位为零且存在仟位和十万以上时，在万仟间补零
else if((i<11)&&(i>8)&&(strArr[intFen-1]!="0")&&(strNow[0]=="万")&&(strNow[2]=="仟"))
strBig = strNum+strDW+"万零"+strBig.substring(1,strBig.length);
//单独处理亿位
else if(i==11)
{
//亿位为零且万全为零存在仟位时，去掉万补为零
if((strArr[intFen-1]=="0")&&(strNow[0]=="万")&&(strNow[2]=="仟"))
strBig ="亿"+"零"+strBig.substring(1,strBig.length);
//亿位为零且万全为零不存在仟位时，去掉万
else if((strArr[intFen-1]=="0")&&(strNow[0]=="万")&&(strNow[2]!="仟"))
strBig ="亿"+strBig.substring(1,strBig.length);
//亿位不为零且万全为零存在仟位时，去掉万补为零
else if((strNow[0]=="万")&&(strNow[2]=="仟"))
strBig = strNum+strDW+"零"+strBig.substring(1,strBig.length);
//亿位不为零且万全为零不存在仟位时，去掉万
else if((strNow[0]=="万")&&(strNow[2]!="仟"))
strBig = strNum+strDW+strBig.substring(1,strBig.length);
//其他正常情况
else
strBig = strNum+strDW+strBig;
}
//拾亿－仟亿中一位为零且其前一位（亿以上）不为零的情况时补零
else if((i<15)&&(i>11)&&(strArr[intFen-1]=="0")&&(strNow[0]!="零")&&(strNow[0]!="亿"))
strBig = "零"+strBig;
//拾亿－仟亿中一位为零且其前一位（亿以上）也为零的情况时跨过
else if((i<15)&&(i>11)&&(strArr[intFen-1]=="0")&&(strNow[0]=="亿"))
{}
//拾亿－仟亿中一位为零且其前一位为亿位且为零的情况时跨过
else if((i<15)&&(i>11)&&(strArr[intFen-1]=="0")&&(strNow[0]=="零"))
{}
//亿位为零且不存在仟万位和十亿以上时去掉上次写入的零
else if((i<15)&&(i>11)&&(strArr[intFen-1]!="0")&&(strNow[0]=="零")&&(strNow[1]=="亿")&&(strNow[3]!="仟"))
strBig = strNum+strDW+strBig.substring(1,strBig.length);
//亿位为零且存在仟万位和十亿以上时，在亿仟万间补零
else if((i<15)&&(i>11)&&(strArr[intFen-1]!="0")&&(strNow[0]=="零")&&(strNow[1]=="亿")&&(strNow[3]=="仟"))
strBig = strNum+strDW+"亿零"+strBig.substring(2,strBig.length);
else
strBig = strNum+strDW+strBig;
strFen = strFen.substring(0,intFen-1);
intFen = strFen.length;
strArr = strFen.split("");
}
return strBig;
}catch(err){
return ""; //若失败则返回原值
}
}
public class Money
{ public Money()
{
}
public static void main(String[] args)
{
Money money1 = new Money();
System.out.println(Money.changeToBig("74329472340.23"));
System.out.println(Money.changeToBig("072340.20"));
System.out.println(Money.changeToBig("0.23"));
System.out.println(Money.changeToBig("700040.03"));
System.out.println(Money.changeToBig("740.00"));
System.out.println(Money.changeToBig("100001000.00"));
}
public static String changeToBig(String value)
{
if(null == value || "".equals(value.trim()))
return "零"; String strCheck,strArr,strFen,strDW,strNum,strBig,strNow;
double d = 0;
try
{
d = Double.parseDouble(value);
}
catch(Exception e)
{
return "数据"+value+"非法！";
} strCheck = value+".";
int dot = strCheck.indexOf(".");
if(dot > 12)
{
return "数据"+value+"过大，无法处理！";
} try
{
int i = 0;
strBig = "";
strDW = "";
strNum = "";
long intFen = (long)(d*100);
strFen = String.valueOf(intFen);
int lenIntFen = strFen.length();
while(lenIntFen != 0)
{
i++;
switch(i)
{
case 1:strDW = "分";break;
case 2:strDW = "角";break;
case 3:strDW = "元";break;
case 4:strDW = "拾";break;
case 5:strDW = "佰";break;
case 6:strDW = "仟";break;
case 7:strDW = "万";break;
case 8:strDW = "拾";break;
case 9:strDW = "佰";break;
case 10:strDW = "仟";break;
case 11:strDW = "亿";break;
case 12:strDW = "拾";break;
case 13:strDW = "佰";break;
case 14:strDW = "仟";break;
}
switch (strFen.charAt(lenIntFen-1)) //选择数字
{
case '1':strNum = "壹";break;
case '2':strNum = "贰";break;
case '3':strNum = "叁";break;
case '4':strNum = "肆";break;
case '5':strNum = "伍";break;
case '6':strNum = "陆";break;
case '7':strNum = "柒";break;
case '8':strNum = "捌";break;
case '9':strNum = "玖";break;
case '0':strNum = "零";break;
}
//处理特殊情况
strNow = strBig;
//分为零时的情况
if((i==1) && (strFen.charAt(lenIntFen-1) == '0'))
strBig = "整";
//角为零时的情况
else if((i==2)&&(strFen.charAt(lenIntFen-1)=='0'))
{ //角分同时为零时的情况
if(!strBig.equals("整"))
strBig = "零"+strBig;
}
//元为零的情况
else if((i==3)&&(strFen.charAt(lenIntFen-1)=='0'))
strBig = "元"+strBig;
//拾－仟中一位为零且其前一位（元以上）不为零的情况时补零
else if((i<7)&&(i>3)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)!='零')&&(strNow.charAt(0)!='元'))
strBig = "零"+strBig;
//拾－仟中一位为零且其前一位（元以上）也为零的情况时跨过
else if((i<7)&&(i>3)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='零'))
{}
//拾－仟中一位为零且其前一位是元且为零的情况时跨过
else if((i<7)&&(i>3)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='元'))
{}
//当万为零时必须补上万字
else if((i==7)&&(strFen.charAt(lenIntFen-1)=='0'))
strBig ="万"+strBig;
//拾万－仟万中一位为零且其前一位（万以上）不为零的情况时补零
else if((i<11)&&(i>7)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)!='零')&&(strNow.charAt(0)!='万'))
strBig = "零"+strBig;
//拾万－仟万中一位为零且其前一位（万以上）也为零的情况时跨过
else if((i<11)&&(i>7)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='万'))
{}
//拾万－仟万中一位为零且其前一位为万位且为零的情况时跨过
else if((i<11)&&(i>7)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='零'))
{}
//万位为零且存在仟位和十万以上时，在万仟间补零
else if((i<11)&&(i>8)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='万')&&(strNow.charAt(2)=='仟'))
strBig = strNum+strDW+"万零"+strBig.substring(1,strBig.length());
//单独处理亿位
else if(i==11)
{
//亿位为零且万全为零存在仟位时，去掉万补为零
if((strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='万')&&(strNow.charAt(2)=='仟'))
strBig ="亿"+"零"+strBig.substring(1,strBig.length());
//亿位为零且万全为零不存在仟位时，去掉万
else if((strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='万')&&(strNow.charAt(2)!='仟'))
strBig ="亿"+strBig.substring(1,strBig.length());
//亿位不为零且万全为零存在仟位时，去掉万补为零
else if((strNow.charAt(0)=='万')&&(strNow.charAt(2)=='仟'))
strBig = strNum+strDW+"零"+strBig.substring(1,strBig.length());
//亿位不为零且万全为零不存在仟位时，去掉万
else if((strNow.charAt(0)=='万')&&(strNow.charAt(2)!='仟'))
strBig = strNum+strDW+strBig.substring(1,strBig.length());
//其他正常情况
else
strBig = strNum+strDW+strBig;
}
//拾亿－仟亿中一位为零且其前一位（亿以上）不为零的情况时补零
else if((i<15)&&(i>11)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)!='零')&&(strNow.charAt(0)!='亿'))
strBig = "零"+strBig;
//拾亿－仟亿中一位为零且其前一位（亿以上）也为零的情况时跨过
else if((i<15)&&(i>11)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='亿'))
{}
//拾亿－仟亿中一位为零且其前一位为亿位且为零的情况时跨过
else if((i<15)&&(i>11)&&(strFen.charAt(lenIntFen-1)=='0')&&(strNow.charAt(0)=='零'))
{}
//亿位为零且不存在仟万位和十亿以上时去掉上次写入的零
else if((i<15)&&(i>11)&&(strFen.charAt(lenIntFen-1)!='0')&&(strNow.charAt(0)=='零')&&(strNow.charAt(1)=='亿')&&(strNow.charAt(3)!='仟'))
strBig = strNum+strDW+strBig.substring(1,strBig.length());
//亿位为零且存在仟万位和十亿以上时，在亿仟万间补零
else if((i<15)&&(i>11)&&(strFen.charAt(lenIntFen-1)!='0')&&(strNow.charAt(0)=='零')&&(strNow.charAt(1)=='亿')&&(strNow.charAt(3)=='仟'))
strBig = strNum+strDW+"亿零"+strBig.substring(2,strBig.length());
else
strBig = strNum+strDW+strBig;
strFen = strFen.substring(0,lenIntFen-1);
lenIntFen--;
}
return strBig;
}
catch(Exception e)
{
return "";
}
}
}
public String Translate(double ad_je) throws GeneralException {
String chineseMoney = "";
String chineseNum;
String chineseUnit;
String moneyValue;
String valueBit;
String valueTmp = ""; int intp;
int intp1;
int intp2;
int intp3;
int intnum; boolean num=true; Double ld_je; System.out.println("$$$%$%&%^&"+ad_je);
System.out.println(dou2Str(ad_je)); if (ad_je >=1000000000000.00||ad_je <= -1000000000000.00){
throw new GeneralException("err.report.DataOverFlow.Error"); //数据溢出
}else if(ad_je == 0){
chineseMoney = "零圆整";
return chineseMoney;
}else if(ad_je < 0){
num = false;
ad_je = ad_je*(-1);
} chineseNum="零壹贰叁肆伍陆柒捌玖";
chineseUnit="仟佰拾亿仟佰拾万仟佰拾圆角分"; numberFormatter.setGroupingUsed(false);
numberFormatter.setMinimumFractionDigits(2); ld_je = new Double(ad_je);
moneyValue = "$" + numberFormatter.formatDouble(ld_je).trim();
moneyValue = moneyValue.substring(0,moneyValue.length() - 3) + moneyValue.substring(moneyValue.length()-2,moneyValue.length()); intp=0;
chineseMoney="";
for(intp = 0; intp < moneyValue.length(); intp++){
valueBit = moneyValue.substring(moneyValue.length()-1-intp,moneyValue.length()-intp);
if (valueBit.equals("$")){
break;
}
intnum = toInt(valueBit);
chineseMoney = chineseNum.substring( intnum, intnum + 1) + chineseUnit.substring( 13 - intp, 13 - intp + 1) + chineseMoney;
}
intp3=chineseMoney.indexOf("零");
if (intp3 >= 0) {
if ( chineseMoney.indexOf("零分")>=0) {
intp2= chineseMoney.indexOf("零分");
chineseMoney = chineseMoney.substring(0,intp2);
if (chineseMoney.indexOf("零角")>=0) {
intp2 = chineseMoney.indexOf("零角");
chineseMoney = chineseMoney.substring(0,intp2);
}
}else{
if (chineseMoney.indexOf("零角")>=0) {
intp2= chineseMoney.indexOf("零角");
chineseMoney = chineseMoney.substring(0,intp2 + 1 ) + chineseMoney.substring(intp2 + 2);
}
}
intp2 = chineseMoney.indexOf("圆");
if (intp2 >= 0) {
valueTmp = chineseMoney.substring(intp2);
chineseMoney = chineseMoney.substring(0,intp2);
intp2=chineseMoney.length();
if (chineseMoney.substring(intp2 - 1,intp2).equals("零")) {
chineseMoney = chineseMoney.substring(0,intp2 - 1);
}
}
//去角分零
int intc;
int intc1;
String strcc;
Hashtable strww = new Hashtable();
intc=1;
intp1=chineseMoney.indexOf("零");
while (intp1 >= 0){
strcc = new Integer(intc).toString().trim();
if (chineseMoney.substring(intp1,intp1+2).equals("零万")){
strww.put(strcc,chineseMoney.substring(0,intp1)+chineseMoney.substring(intp1 + 1,intp1 + 2));
}else {
if (chineseMoney.substring(intp1,intp1+2).equals("零亿")){
strww.put(strcc,chineseMoney.substring(0,intp1)+chineseMoney.substring(intp1 + 1,intp1 + 2));
}else{
strww.put(strcc,chineseMoney.substring(0,intp1 + 1));
}
}
if (chineseMoney.length() > intp1 + 2){
chineseMoney = chineseMoney.substring(intp1 + 2);
}else
{
chineseMoney="";
}
intp1 = chineseMoney.indexOf("零");
intc = intc + 1;
}
intc1=1;
String strwww = "";
while (intc1< intc) {
strcc = new Integer(intc1).toString().trim();
strwww = strwww + (String)strww.get(strcc);
intc1 = intc1+1;
}
chineseMoney = strwww + chineseMoney + valueTmp;
while (chineseMoney.indexOf("零零")>=0) {
intp1 = chineseMoney.indexOf("零零");
chineseMoney = chineseMoney.substring(0,intp1) + chineseMoney.substring(intp1 + 1);
}
intp1 = chineseMoney.indexOf("零圆");
if (intp1>= 0){
chineseMoney = chineseMoney.substring(0,intp1) + "零" + chineseMoney.substring(intp1 + 1);
}
if (chineseMoney.indexOf("分") < 0){
chineseMoney = chineseMoney + "整";
}
}
intp = chineseMoney.indexOf("零圆");
if (intp>=0){
chineseMoney = chineseMoney.substring(0,intp) + chineseMoney.substring(intp + 1);
}
intp = chineseMoney.indexOf("零万");
if (intp>=0){
chineseMoney = chineseMoney.substring(0,intp) + chineseMoney.substring(intp + 1);
}
intp = chineseMoney.indexOf("零亿");
if (intp>=0){
chineseMoney = chineseMoney.substring(0,intp) + chineseMoney.substring(intp + 1);
}
intp = chineseMoney.indexOf("亿万");
if (intp>=0){
chineseMoney = chineseMoney.substring(0,intp + 1) + chineseMoney.substring(intp + 2);
}
if (chineseMoney.substring(0,1).equals("圆")){
chineseMoney = chineseMoney.substring(1);
if (chineseMoney.substring(0,1).equals("零")){
chineseMoney = chineseMoney.substring(1);
}
}
if(num){
return chineseMoney;
}else{
chineseMoney = "负"+chineseMoney;
return chineseMoney;
}
}
class NumberFormatter {
NumberFormat formatter = NumberFormat.getNumberInstance();
public NumberFormatter() {
formatter.setParseIntegerOnly(false);
}
public String formatDouble(double value) {
return formatter.format(value);
}
public String formatDouble(Double value) {
return formatter.format(value.doubleValue());
}
public String formatFloat(float value) {
return formatter.format(value);
}
public String formatFloat(Float value) {
return formatter.format(value.floatValue());
}
public String formatInteger(int value) {
return formatter.format(value);
}
public String formatInteger(Integer value) {
return formatter.format(value.intValue());
}
public String formatDate(Date value) {
return DateFormat.getDateInstance().format(value);
}
public String formatLong(long value) {
return formatter.format(value);
}
public String formatLong(Long value) {
return formatter.format(value.longValue());
}
public void setGroupingUsed(boolean right) {
formatter.setGroupingUsed(right);
}
public void setMinimumFractionDigits(int bits) {
formatter.setMinimumFractionDigits(bits);
}
}