datestr = "29/Sep/2009:17:09:06";
String gettime = "";
try {
SimpleDateFormat dateFm = new SimpleDateFormat("dd/MMM/yy:HH:mm:ss",new Locale("US"));
java.util.Date dateTime = dateFm.parse(datestr);
dateFm = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
gettime = dateFm.format(dateTime).toString();
} catch (Exception e) {
e.printStackTrace();
}
system.out.println(gettime);以上这段代码在win上面没问题,在Linux下就出错,两边java版本都是1.5的,真是想不通,只果真是操作系统的问题,大家有什么好的办法来处理 "29/Sep/2009:17:09:06" 这种日期格式吗
String gettime = "";
try {
SimpleDateFormat dateFm = new SimpleDateFormat("dd/MMM/yy:HH:mm:ss",new Locale("US"));
java.util.Date dateTime = dateFm.parse(datestr);
dateFm = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
gettime = dateFm.format(dateTime).toString();
} catch (Exception e) {
e.printStackTrace();
}
system.out.println(gettime);以上这段代码在win上面没问题,在Linux下就出错,两边java版本都是1.5的,真是想不通,只果真是操作系统的问题,大家有什么好的办法来处理 "29/Sep/2009:17:09:06" 这种日期格式吗
这句应该是System.out.println(gettime);吧楼主你测试的linux系统是什么发行版的?
在我这儿测试你的代码没出错呀
输出结果2009-09-29 17:09:06import java.util.*;
import java.text.*;public class Test{
public static void main(String [] args){
String datestr = "29/Sep/2009:17:09:06";
String gettime = "";
try {
SimpleDateFormat dateFm = new SimpleDateFormat("dd/MMM/yy:HH:mm:ss
",new Locale("US"));
Date dateTime = dateFm.parse(datestr);
dateFm = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
gettime = dateFm.format(dateTime).toString();
} catch (Exception e) {
e.printStackTrace();
}
System.out.println(gettime);
}
}
[root@xxxx root]# lsb_release -a
LSB Version: 1.3
Distributor ID: RedHatEnterpriseAS
Description: Red Hat Enterprise Linux AS release 3 (Taroon Update 3)
Release: 3
Codename: TaroonUpdate3
[root@sms1 root]# rpm -q redhat-release
redhat-release-3AS-7.3这个问题真想不通,那位帮帮忙啊