ZipInputStream类读取普通zip文件的问题

Question

和中文无关
你应该贴出代码给大家看

Answer 1

//1.zip其中压缩了一个文件为"测试.txt"            
         ZipInputStream zin=new ZipInputStream(new FileInputStream("d:\\1.zip"));
         ZipEntry ze;
         while((ze=zin.getNextEntry())!=null)
         {
           if(!ze.isDirectory())
           {
              System.out.println("文件名："+ze.getName());
            }
            else
            {
               System.out.println("目录名："+ze.getName());
            }
            zin.closeEntry();
          }
          zin.close();