怎么从客户端通过Socket向服务器发送一条信息,并在服务器接收呢?(急!!!!!!!)

为什么在SERVER和在CLIENT都用　
dis = new ObjectInputStream(s.getInputStream());
dos = new ObjectOutputStream(s.getOutputStream());
就是个死循环呢?
如果我接收客户端的信息,就要把客户端的dis那个去掉,就能接收到,否则就是死循环,如果我要向客户断发送一信息,那么就要把服务器端的dis去掉,要么也是死循环.
难道我在服务器端要建两个程序么?一个负责接受客户端的信息,一个负责给客户端下载文件?

不会吧，发送完用flush()刷新一下

我有刷新哪,请您看一下我的代码吧.我实在不知道哪有问题了.客户端程序:
public class s
{
  private Socket s = null;
  private ObjectInputStream dis = null;
  private ObjectOutputStream dos = null;
  private FileOutputStream fos = null;
  private File file = null;  public void sss()
  {
    try
    {
      s = new Socket("127.0.0.1", 1200);      dis = new ObjectInputStream(s.getInputStream());
      dos = new ObjectOutputStream(s.getOutputStream());
      dos.writeObject("e://xml//Match.xsl");
      dos.flush();
      dos.close();
      dis.close();
      s.close();
    }
    catch (Exception e)
    {
      System.err.println("IOError in socketClient.SocketClient(): " + e.getMessage());
    }  }}***********************************************************
服务器端程序:
public class SocketServer
{
  private ServerSocket ss = null;
  private Socket s = null;
  private String filename = null;
  private boolean b = true;
  private ObjectInputStream dis = null;
  private ObjectOutputStream dos = null;
  private FileInputStream fis = null;
  private File file = null;
  public SocketServer()
  {
    System.out.println("server is running......");
    try
    {
      ss = new ServerSocket(1200);
    }
    catch (IOException e)
    {
      System.err.println("IOError in SocketServer.SocketServer(): " + e.getMessage());
    }
  }  public void waitForClient()
  {
    try
    {
      while (b)
      {
s = ss.accept();
dis = new ObjectInputStream(s.getInputStream());
      dos = new ObjectOutputStream(s.getOutputStream());
      String filename = (String)dis.readObject();
      System.out.println("filename: " + filename);      fis = new FileInputStream(file);
      System.out.println("222222222");      byte[] b = new byte[1024];
      while (fis.read(b) != -1)
      {
dos.write(b);
      }
      fis.close();      dos.writeObject(file.getName());
      dos.close();
      dis.close();      s.close();
      }
    }
    catch (Exception e)
    {
      System.err.println("IOError in SocketServer.waitForClient(): " + e.getMessage());
    }
  }
}

1、你这种方式是传不过去的，ObjectOutputStream是可以传对象，但File对象只是封装了此File相关的描述信息，File的内容没有被发送。
2、用socket传文件，一般的做法是用流的方式来传
请参考以下代码：
--------------------------------------------------------
import java.io.*;
import java.net.*;//对每一笔客户请求，另起一个线程
class ThreadServer extends Thread{  private Socket socket;
  private DataInputStream inStream=null;
  private DataOutputStream outStream=null;
  private FileInputStream fin = null;  public ThreadServer(Socket sock){
    this.socket = sock;
  }  public synchronized void run(){
  boolean bool = false;
  try{
  inStream=new DataInputStream(socket.getInputStream());
  outStream=new DataOutputStream(socket.getOutputStream());
  fin = new FileInputStream("C:/temp/socket/200212060001_ds.zip");
  //socket.setSoTimeout(3000);
  byte[] b = new byte[200];
  int i;
  while((i=fin.read(b))!=-1){
  outStream.write(b);
  }
  fin.close();
  socket.close();

  }catch(IOException ex){
  System.out.println(ex);
  }
  }}-------------------------------------------------------
import java.net.*;
import java.io.*;public class SocketClient{
Socket s=null;
DataInputStream inStream=null;
DataOutputStream outStream=null;
FileOutputStream fout = null;public SocketClient() {
try{
s=new Socket("192.9.207.52",765); //把这里的IP改成你运行SocketServer.class的IP
inStream=new DataInputStream(s.getInputStream());
outStream=new DataOutputStream(s.getOutputStream());
fout = new FileOutputStream("C:/temp/socket/test11.zip");
s.setSoTimeout(3000);
waitData();
}catch(Exception e){
System.out.println(e.toString());
}
}void waitData(){
try{
byte[] b = new byte[200];
int i;
while((i=inStream.read(b))!=-1){
fout.write(b);
}
fout.flush();
fout.close();
s.close();
}catch(Exception e){
System.out.println(e.toString());
}
}    public static void main(String[] args) {
SocketClient socketClient1 = new SocketClient();
}
}
------------------------------------------------------------------
import java.io.*;
import java.net.*;
import java.io.BufferedInputStream;public class SocketServer {
ServerSocket ss=null;
Socket s=null;
DataInputStream inStream=null;
DataOutputStream outStream=null;
FileInputStream fin = null;public SocketServer() {
  try{
    ss=new ServerSocket(765);
    s.setSoTimeout(3000);
  }catch(Exception e){
    System.out.println(e.toString());
  }
}void waitForClient(){
  try{
  //起一个监听，等待客户端的响应，一旦有回应，将之分派给线程来完成，主程序继续监听
  while(true){
  s=ss.accept();
  ThreadServer thread = new ThreadServer(s);
  thread.start();
  }
  }catch(Exception e){
    System.out.println(e.toString());
  }
}public static void main(String[] args) {
SocketServer socketServer1 = new SocketServer();
socketServer1.waitForClient();
}
}
在win2k & jdk1.3上调试通过

谢谢楼上的
但我现在要在JSP里用这个方法,当一个用户点一个文件要下载时,我要动态的传给SocketServer一个路径+文件名,然后SocketServer据此代替您的C:/temp/socket/test11.zip,然后我要将文件名传回客户端,用它来生成一个文件存在客户的机器上,我又该怎么做呢?

你的问题好象是要用文件下载来完成，这种需求好象不适合用socket吧！
client端通过IE访问server，访问的端口都不一样，再说IE不具备socket　client的身份，要将请求传递给约定的端口不太容易。
　　用户触发jsp,jsp请求socketserver，那通信就成了socketserver与web server之间进行了.

对,楼上的,就是这么回事,我就是要通过WEB SERVER来下载.我该怎么办呢?

将你的文件地址转成URL,在JSP中将链接定向到此URL
文件的格式只能是有限种的，不然有些可能变成在IE中打开了。具体格式参考网络蚂蚁等。
建议将文件包成zip或jar等常用格式，你自己总下载过ZIP吧

调试易

怎么从客户端通过Socket向服务器发送一条信息,并在服务器接收呢?(急!!!!!!!)

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