普通办法.
String[] str = {"abc","ab","abc"};
Hashtable ht = new Hashtable();
for(int i=0;i<str.length;i++)
{
ht.put(str[i],str[i]);
}
Enumeration e = ht.keys();
str = new String[ht.size()];
.....
String[] str = {"abc","ab","abc"};
Hashtable ht = new Hashtable();
for(int i=0;i<str.length;i++)
{
ht.put(str[i],str[i]);
}
Enumeration e = ht.keys();
str = new String[ht.size()];
.....
Hashtable ht = new Hashtable();
for(int i=0;i<str.length;i++)
{
ht.put(str[i],str[i]);
}
Enumeration keys = ht.keys();
str = new String[ht.size()];
int index = 0;
foreach(object obkey in keys)
{
str[index] = obkey.ToString();
index++;
}
String[] str = {"abc","ab","abc"};
Set s= new java.util.HashSet();
str = new String[s.size()];
s.toArray(str);
for (int i=0;i<str.length;i++){
System.out.println(str[i]);
}
public static void main(String[] args){
String[] str = {"abc","ab","abc"};
Set s= new java.util.HashSet();
for (int i=0 ;i<str.length;i++){
s.add(str[i]);
}
str = new String[s.size()];
s.toArray(str);
for (int i=0;i<str.length;i++){
System.out.println(str[i]);
}
}
........
}