HELP!!!APPLET小小小游戏求助！

Question

16个格子对应一个4，4坐标系1,1     1,2     1,3     1,4
2,1     2,2     2,3     2,4
3,1     3,2     3,3     3,4
4,1     4,2     4,3     4,4记住当前#button的坐标，只有坐标值x+y之和，同#所在坐标X+Y之和相减的绝对值=1时(=0也不行)，其对应坐标中的按钮才能够移动到#原来的位置。然后将#坐标重新变一下。这就是移动的规则。至于判断是否完成的规则就太简单了，遍历坐标系一便就成了。

Answer 1

反正没事，给你写了一下，实现如下：
程序稍改了一下，如改成JApplet了，你可再改回去。写了main方法，可直接运行。
两按钮相邻的方法没有用 advanced(超越) 的方法，（4，1）和（2，4）和差一，显然不在一块。没有多想，用了笨办法。程序由按“＃”按钮开始。我没那个本事玩通关，哈哈。import java.awt.*;
import java.awt.event.*;
import java.applet.*;
import javax.swing.*;public class Puzzle extends JApplet implements java.awt.event.ActionListener {
    private Panel panel;
    private Button button[];    public Puzzle() {
        panel=new Panel();
        button=new Button[16];
        int i;
        for (i=0;i<button.length;i++) {
            button[i]=new Button(Integer.toString(i));
            button[i].setBackground(new Color(204,204,204));
        }
        button[0].setLabel("#");        panel.setLayout(new GridLayout(4,4));
        panel.setBackground(Color.blue);
        panel.setSize(300,300);
        getContentPane().add(panel);
        for (i=button.length-1;i>=0;i--)
            panel.add(button[i]);    }    public void init() {
// Puzzle puzzle = new Puzzle();
        for(int i=0;i<16;i++) {
            button[i].addActionListener(this);
        }
    }    private int sharpIndex = -1;    public void actionPerformed(ActionEvent e) {
        Button b = (Button)e.getSource();
        int index = 0;
        for(int i=0;i<16;i++) {
            if(button[i].equals(b))
                index = i;
        }        //start
        if(b.getLabel().equals("#")) {
            sharpIndex = index;
            b.setBackground(Color.red);
        } else {
            if(sharpIndex == -1 || index == sharpIndex)
                return;
            if(isNearSharp(index)) {
                button[sharpIndex].setBackground(new Color(204,204,204));
                button[sharpIndex].setLabel(b.getLabel());
                b.setBackground(Color.red);
                b.setLabel("#");
                sharpIndex = index;
                checkSuccess();
            } else {
                JOptionPane.showMessageDialog(this,"move error!","Error",JOptionPane.INFORMATION_MESSAGE);
            }
        }
    }    private boolean isNearSharp(int clickedIndex) {
        switch (clickedIndex) {
            case 0:
                if(sharpIndex == 1 || sharpIndex == 4)
                    return true;
                break;
            case 1:
                if(sharpIndex == 0 || sharpIndex == 2 || sharpIndex == 5)
                    return true;
                break;
            case 2:
                if(sharpIndex == 1 || sharpIndex == 3 || sharpIndex == 6)
                    return true;
                break;
            case 3:
                if(sharpIndex == 2 || sharpIndex == 7)
                    return true;
                break;
            case 4:
                if(sharpIndex == 0 || sharpIndex == 5 || sharpIndex == 8)
                    return true;
                break;
            case 5:
                if(sharpIndex == 1 || sharpIndex == 4 || sharpIndex == 6 || sharpIndex == 9)
                    return true;
                break;
            case 6:
                if(sharpIndex == 2 || sharpIndex == 5 || sharpIndex == 7 || sharpIndex == 10)
                    return true;
                break;
            case 7:
                if(sharpIndex == 3 || sharpIndex == 6 || sharpIndex == 11)
                    return true;
                break;
            case 8:
                if(sharpIndex == 4 || sharpIndex == 9 || sharpIndex == 12)
                    return true;
                break;
            case 9:
                if(sharpIndex == 5 || sharpIndex == 8 || sharpIndex == 10 || sharpIndex == 13)
                    return true;
                break;
            case 10:
                if(sharpIndex == 6 || sharpIndex == 9 || sharpIndex == 11 || sharpIndex == 14)
                    return true;
                break;
            case 11:
                if(sharpIndex == 7 || sharpIndex == 10 || sharpIndex == 15)
                    return true;
                break;
            case 12:
                if(sharpIndex == 8 || sharpIndex == 13)
                    return true;
                break;
            case 13:
                if(sharpIndex == 9 || sharpIndex == 12 || sharpIndex == 14)
                    return true;
                break;
            case 14:
                if(sharpIndex == 10 || sharpIndex == 13 || sharpIndex == 15)
                    return true;
                break;
            case 15:
                if(sharpIndex == 11 || sharpIndex == 14)
                    return true;
                break;
            default:
                break;
        }
        return false;
    }    private void checkSuccess() {
        if(button[0].getLabel().equals("#")) {
            boolean isSuccess = true;
            for(int i=1;i<16;i++) {
                if(!button[i].getLabel().equals(""+(16-i))) {
                    isSuccess = false;
                    break;
                }
            }
            if(isSuccess) {
                JOptionPane.showMessageDialog(this,"game successed!","Success",JOptionPane.INFORMATION_MESSAGE);
            }
        }
    }    public static void main(String[] args) {
        Puzzle applet = new Puzzle();
        applet.init();
        applet.start();
        JFrame frame = new JFrame();
        frame.setContentPane(applet.getContentPane());
        frame.setSize(new Dimension(900,650));
        frame.addWindowListener(new WindowAdapter() {
            public void windowClosing(WindowEvent e) {
                System.exit(0);
            }
        });
        frame.setVisible(true);
    }
}

Answer 2

to  nil2000(我爱北京天安门) 你的代码太长了，顶多用一半代码量就够了。

Answer 3

不长啊，就是判断相临的方法isNearSharp(int clickedIndex)长了些，你可以改写算法，应该10行搞定。 我怕想。
我玩到最后，也像 namowen(寒号不已) 一样，有两个块倒了。好像游戏不能通关。