征集时间判断方法

Question

date1.getTime()-date2.getTime() <= 5*24*60*60*1000

Answer 1

用于判断某一天是否8位标准日期
public boolean isStandardDate(String sourceString)
  {
    String date = sourceString;
    if(date == null)
    {
      return false;
    }
    else if(date.length()!=8)
    {
      return false;
    }
    else if(!isNumber(date))
    {
      return false;
    }
    else
    {
      String year = date.substring(0,4);
      String month = date.substring(4,6);
      String day = date.substring(6,8);
      if((month.compareTo("12")>0)||(month.compareTo("01")<0)||(day.compareTo("31")>0)||(day.compareTo("01")<0))
      {
        return false;
      }
      else
      {
        int Year = Integer.parseInt(year);
        if(month.compareTo("08")<0)
        {
          if(month.equals("02"))
          {
            if((Year%4==0)&&((Year%100!=0))||(Year%400==0))
            {
              if(day.compareTo("29")>0)
              {
                return false;
              }
              else
              {
                return true;
              }
            }
            else
            {
              if(day.compareTo("28")>0)
              {
                return false;
              }
              else
              {
                return true;
              }
            }
          }
          else
          {
            int Month = Integer.parseInt(month);
            if(Month%2==0)
            {
              if(day.compareTo("30")>0)
              {
                return false;
              }
              else
              {
                return true;
              }
            }
            else
            {
              return true;
            }
          }
        }
        else
        {
          int Month = Integer.parseInt(month);
          if(Month%2==0)
          {
            return true;
          }
          else
          {
            if(day.compareTo("30")>0)
            {
              return false;
            }
            else
            {
              return true;
            }
          }
        }
      }
    }
  }

Answer 2

/**功能：日期调整。返回值：调整后的8位标准日期。
   * @param sourceString
   * @param addDays
   */
  public String dateAdjust(String sourceString, int addDays)
  {
    String returnString = sourceString;
    if(isStandardDate(sourceString))
    {
      SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
      Date dt = sdf.parse(sourceString, new ParsePosition(0));
      Calendar cal = Calendar.getInstance();
      cal.setTime(dt);
      cal.add(cal.DATE, addDays);
      Date dt1 = cal.getTime();
      StringBuffer strBuffer = new StringBuffer();
      strBuffer.append("");
      returnString = sdf.format(dt1, strBuffer, new FieldPosition(0)).toString();
    }
    return returnString;
  }

Answer 3

靠，太复杂了SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd hhmm");
try{
 sdf.parse(strDate)
}catch(ParseException){}

Answer 4

靠，太复杂了SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd hhmm");
try{
 sdf.parse(strDate)
 return true;
}catch(ParseException){
 return false;
}