怎么判断取得服务器的日期是否是某月的最后一天？

Question

public static boolean isLeapYear(int year) {
      
      if (year > 1582 && year % 4 == 0 &&
         (year % 100 != 0 || (year % 100 == 0 && year % 400 == 0)))
         return true;
      else
         return false;
   }  
   public static int getMonthDays(int year, int month) {
      int day = 0;
      switch (month) {
         case 1:
         case 3:
         case 5:
         case 7:
         case 8:
         case 10:
         case 12:
            day = 31;
            break;
         case 4:
         case 6:
         case 11:
            day = 30;
            break;
         case 9:
            if (year == 1582)
               day = 20;
            else
               day = 30;
            break;
         case 2:
            if (isLeapYear(year))
               day = 29;
            else
               day = 28;
            break;
         default:
            System.out.println("MyDateTime.getMonthDays: Month(" + month + ") is beyond : 1-12。");
            break;
      }
      return day;
   }//这个是你最终调用的函数
   public static boolean isLastDay(int year, int month,int day)
   {
      int monthday = getMonthDays(year,month);
      if (day > monthday)
      {
          System.out.println(year+"year"+month+"month"+day+"day is error date!!\n");
              return false;
      }
      else if(day < monthday)
           return false;      return true;
   }

Answer 1

我以前遇到过这样的问题，也找过clander的方法，没有找到。后来自己写了一个程序，很简单的，就是把年月作为参数返回最后一天，里面都是swich case这样的东西，很难看。要是你最后实在没有办法了，就这样吧，hohohooho
    private int getDay(int year,int month){
        int returnInt=31;
        switch(month){
            case 1:
                returnInt=31;
                break;
            case 2:
                if(month==2 &&  year%4==0){
                    returnInt=29;
                }
                if(year%100 == 0 && year%400 != 0){
                    returnInt=28;
                }
                if(year%100 == 0 && year%400 == 0){
                    returnInt=29;
                }
                break;
            case 3:
                returnInt=31;
                break;
            case 4:
                returnInt=30;
                break;
            case 5:
                returnInt=31;
                break;
            case 6:
                returnInt=30;
                break;
            case 7:
                returnInt=31;
                break;
            case 8:
                returnInt=31;
                break;
            case 9:
                returnInt=30;
                break;
            case 10:
                returnInt=31;
                break;
            case 11:
                returnInt=30;
                break;
            case 12:
                returnInt=31;
                break;
            default:
                returnInt=31;
                break;
            }
        return returnInt;
    }
大概是这样的,不过我要用的是最后一天，你可以判断一下

Answer 2

Calendar now=Calendar.getInstance();
now.add(Calendar.DATE,-now.get(Calendar.DATE)+1);
now.add(Calendar.MONTH,1);
now.add(Calendar.DATE,-1);

Answer 3

Calendar now=Calendar.getInstance();
now.add(Calendar.DATE,-now.get(Calendar.DATE)+1);
now.add(Calendar.MONTH,1);
now.add(Calendar.DATE,-1);

Answer 4

看来只能用 arke(keke) 或 vivanSun(骆驼)的方法！我也是再找Calendar里
面是否有，也是没有找到！谢谢两位！

Answer 5

也许这个方法更好
Date todate = new Date();
Date secdate = new Date(todate.getYear(),todate.getMonth(),todate.getDate()+1);
if (secdate.getDate()<2)
{
System.out.println("today is the last of this month");
}
else
{
System.out.println("today is not the last of this month");
}