请问怎么用java定制平面式的反转按纽，就象IE浏览器上的“收藏”按纽。

Question

不太清楚，你可以试这在按下去的时候控制按纽状态.

Answer 1

void this_mouseEntered(MouseEvent e) {
    if(isEnabled()){
      setCursor(Cursor.getPredefinedCursor(Cursor.HAND_CURSOR));
      setBorder(BorderFactory.createRaisedBevelBorder());
    }
  }/**
* @description
* 鼠标按下
* @param e
* 修改描述 无
*/
  void this_mousePressed(MouseEvent e) {
    if(isEnabled())
      setBorder(BorderFactory.createLoweredBevelBorder());
  }/**
* @description
* 鼠标离开按钮
* @param e
* 修改描述 无
*/
  void this_mouseExited(MouseEvent e) {
    if(isEnabled()){
      setCursor(Cursor.getPredefinedCursor(Cursor.DEFAULT_CURSOR));
      setBorder(BorderFactory.createEtchedBorder());
    }
  }/**
* @description
* 鼠标按钮放开
* @param e
* 修改描述 无
*/
  void this_mouseReleased(MouseEvent e) {
    if(isEnabled())
      setBorder(BorderFactory.createRaisedBevelBorder());
  }/**
* @description
* 按钮失去焦点
* @param e
* 修改描述 无
*/
  void this_focusLost(FocusEvent e) {
    setBorder(BorderFactory.createEtchedBorder());
  }/**
* @description
* 按钮得到焦点
* @param e
* 修改描述 无
*/
  void this_focusGained(FocusEvent e) {
    setBorder(BorderFactory.createEtchedBorder());
  }/**
* @description
* 按钮状态改变
* @param e
* 修改描述 无
*/
  void this_stateChanged(ChangeEvent e) {
    if(!this.isEnabled())
       setBorder(BorderFactory.createEtchedBorder());  }