紧急请教用什么函数判断输入的不是int类型?

Question

这样对麽,谢谢!
boolean inputNotOK=true;
while(inputNotOK)
{
   try
   {
      int integerVariable=Integer.parseInt(capacityEntered);
      inputNotOK=false;
   }
   catch(java.lang.Exception exception)
   {
      System.out.println("You should set a int number,Please try again");  
   }
}

Answer 1

NumberFormatException - if the string does not contain a parsable integer.boolean inputNotOK=true;
while(inputNotOK)
{
  try
  {
      int integerVariable=Integer.parseInt(capacityEntered);
      inputNotOK=false;
  }
  catch(NumberFormatException exception)
  {
      System.out.println("You should set a int number,Please try again");  
  }
} 

Answer 2

boolean inputNotOK = true; 
            while(inputNotOK )
            {
               try 
               {  
                    int integerVariable=Integer.parseInt(capacityEntered);
                    inputNotOK= false;
               } 
               catch (NumberFormatException exception)
               { 
                    displayArea.setText( "You should set an int number, please try again!");
               } // End try catch;
               
            } // End while.
结果是无限循环，在文本框内不挺的显示You should set an int number, please try again!"在catch中加入 break还出错，请指教，十分感谢

Answer 3

在catch把 inputNotOk=false;运行时也出错。

Answer 4

boolean inputNotOK = true; 
            while(inputNotOK )
            {
              try 
              {  
                   /******************************************/
                   //you must do something to change 
                   //   the value of "capacityEntered" !!!
                  
                    int integerVariable=Integer.parseInt(capacityEntered);
                    inputNotOK= false;
              } 
              catch (NumberFormatException exception)
              { 
                    displayArea.setText( "You should set an int number, please try again!");
              } // End try catch;
              
            } // End while.

Answer 5

我想既然能输出You should set an int number, please try again就是捕获到了错误，1为什么不停的循环呢

Answer 6

boolean inputNotOK = true; 
              while ( inputNotOK) 
              { 
                   try 
                    { 
                             int integerVariable= Integer.valueOf( capacityEntered.trim() ).intValue(); 
                              inputNotOK = false; 
                    } 
                    catch ( java.lang.Exception exception)
                    {
                         displayArea.setText( "cannot understand, please try again!");
                     } // End try/ catch; 
                } // End while. 
还是不停循环

Answer 7

boolean inputNotOK = true; 
              while ( inputNotOK) 
              { 
                  try 
                    { 
                            int integerVariable= Integer.valueOf( capacityEntered.trim() ).intValue(); 
                              
                    } 
                    catch ( java.lang.Exception exception)
                    {
                        inputNotOK = false;    
                        displayArea.setText( "cannot understand, please try again!");
                    } // End try/ catch; 
                } // End while. 

Answer 8

不循环了，但是出现错误拉
 可能是int integerVariable= Integer.valueOf( capacityEntered.trim() ).intValue(); 
写的不对,我输的是f测试
Exception occureed during event dispatching:
java.lang.NumberFormatException:f
            at java.lang.Integer.parseInt(Unknown Source)
            at java.lang.Integer.parseInt(Unknown Source)
            at PlayListGUI.actionPerformed(PlayListGUI.java:116)
            at java.awt.Button.processActionEvent(Unknown Source)
.......................

Answer 9

parseInt()试试!
我记不清了

Answer 10

int integerVariable=Integer.parseInt(capacityEntered);
编译通得过，运行时错误一样，我实在不知道怎么写这句，谁能帮帮我

Answer 11

if(e.getSource()==capacityButton)
{
String capacityEntered=capacityField.getText(); // if capacity not entered
if(capacityEntered.length()==0)
{
displayArea.setText("Capacity of songs must be entered!");
return;
} try 
{  
int integerVariable=Integer.parseInt(capacityEntered);

} 
catch (NumberFormatException exception)
{ 
displayArea.setText( "You should set an int number, please try again!");
return;
}// End try catch; if(integerVariable<1)
{
displayArea.setText("Unavailable capacity");
return;
}
            
// if everything is okay then specify the capacity
list=new PlayList(Integer.parseInt(capacityEntered));
}