应该不难吧,
String str = new String(...);
Double dbl = new Double(str);
不过要注意,你这个string的值如果根本不是double,那么肯定出错。
String str = new String(...);
Double dbl = new Double(str);
不过要注意,你这个string的值如果根本不是double,那么肯定出错。
调试欢乐多
===================================
integer to String :
int i = 42;
String str = Integer.toString(i);
or
String str = "" + i
double to String :
String str = Double.toString(i);
long to String :
String str = Long.toString(l);
float to String :
String str = Float.toString(f);String to integer :
str = "25";
int i = Integer.valueOf(str).intValue();
or
int i = Integer.parseInt(str);
String to double :
double d = Double.valueOf(str).doubleValue();
String to long :
long l = Long.valueOf(str).longValue();
or
long l = Long.parseLong(str);
String to float :
float f = Float.valueOf(str).floatValue();decimal to binary :
int i = 42;
String binstr = Integer.toBinaryString(i);decimal to hexadecimal :
int i = 42;
String hexstr = Integer.toString(i, 16);
or
String hexstr = Integer.toHexString(i);hexadecimal (String) to integer :
int i = Integer.valueOf("B8DA3", 16).intValue();
or
int i = Integer.parseInt("B8DA3", 16);
ASCII code to String
int i = 64;
String aChar = new Character((char)i).toString();integer to ASCII code (byte)
char c = 'A';
int i = (int) c; // i will have the value 65 decimalTo extract Ascii codes from a String
String test = "ABCD";
for ( int i = 0; i < test.length(); ++i ) {
char c = test.charAt( i );
int i = (int) c;
System.out.println(i);
}integer to boolean
b = (i != 0);
boolean to integer
i = (b)?1:0;
note :To catch illegal number conversion, try using the try/catch mechanism.
try{
i = Integer.parseInt(aString);
}
catch(NumberFormatException e)
{
}
类似于Delphi的formatfloat('0.00',1.2345)->1.23
double d ;d =Double.parseDouble(str);java.text.DecimalFormat df = new DecimalFormat("###,##0.000");
System.out.print(df.format(d));
这么简单的问题,我看上面各位的回答够详细了,建议版主把这家伙从csdn踢出去!